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A mass of 100 gm is tied to one end of string 2 m long. The body is revolving in a horizontal circle making a maximum of 200 revolutions per min. The other end of the string is fixed at the centre of the circle of revolution. The maximum tension that the string can bear is (approximately)
  • a)
    8.76 N
  • b)
    8.94 N
  • c)
    89.42 N
  • d)
    87.64 N
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A mass of 100 gm is tied to one end of string 2 m long. The body is re...
Given:
Mass of the object, m = 100 g = 0.1 kg
Length of the string, l = 2 m
Maximum revolutions per minute, f = 200 rpm

To find: Maximum tension that the string can bear

Formula used:
T = mω²l
where T is tension, m is mass, ω is angular velocity and l is length of the string.

Calculation:
1 minute = 60 seconds
Maximum angular velocity, ω = 2πf = 2π (200/60) = 20π rad/sec
Length of the string, l = 2 m
Mass of the object, m = 0.1 kg

Substituting the given values in the formula, we get:
T = mω²l = (0.1) (20π)² (2) ≈ 87.64 N

Therefore, the maximum tension that the string can bear is approximately 87.64 N.

Answer: d) 87.64 N
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A mass of 100 gm is tied to one end of string 2 m long. The body is revolving in a horizontal circle making a maximum of 200 revolutions per min. The other end of the string is fixed at the centre of the circle of revolution. The maximum tension that the string can bear is (approximately)a)8.76 Nb)8.94 Nc)89.42 Nd)87.64 NCorrect answer is option 'D'. Can you explain this answer?
Question Description
A mass of 100 gm is tied to one end of string 2 m long. The body is revolving in a horizontal circle making a maximum of 200 revolutions per min. The other end of the string is fixed at the centre of the circle of revolution. The maximum tension that the string can bear is (approximately)a)8.76 Nb)8.94 Nc)89.42 Nd)87.64 NCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A mass of 100 gm is tied to one end of string 2 m long. The body is revolving in a horizontal circle making a maximum of 200 revolutions per min. The other end of the string is fixed at the centre of the circle of revolution. The maximum tension that the string can bear is (approximately)a)8.76 Nb)8.94 Nc)89.42 Nd)87.64 NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mass of 100 gm is tied to one end of string 2 m long. The body is revolving in a horizontal circle making a maximum of 200 revolutions per min. The other end of the string is fixed at the centre of the circle of revolution. The maximum tension that the string can bear is (approximately)a)8.76 Nb)8.94 Nc)89.42 Nd)87.64 NCorrect answer is option 'D'. Can you explain this answer?.
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