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An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by
  • a)
    gR2/R + h
  • b)
    gR
  • c)
    gR/R + h
  • d)
    √gR2/R + h
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
An earth satellite of mass m revolves in a circular orbit at a height ...
The velocity of a satellite in a circular orbit is given by:

v = √(GM/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the orbit.

Since the satellite is at a height h from the surface of the Earth, the radius of the orbit is R + h. Therefore, the velocity of the satellite is:

v = √(GM/(R + h))

To simplify this expression, we can use the fact that g = GM/R². Rearranging this equation, we get GM = gR². Substituting this into the velocity equation, we have:

v = √(gR²/(R + h))

Therefore, the correct answer is:

a) gR²/(R + h)
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Community Answer
An earth satellite of mass m revolves in a circular orbit at a height ...
Mv2/r+h= Gmm/r+h
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An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given bya)gR2/R + hb)gRc)gR/R + hd)√gR2/R + hCorrect answer is option 'D'. Can you explain this answer?
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An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given bya)gR2/R + hb)gRc)gR/R + hd)√gR2/R + hCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given bya)gR2/R + hb)gRc)gR/R + hd)√gR2/R + hCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given bya)gR2/R + hb)gRc)gR/R + hd)√gR2/R + hCorrect answer is option 'D'. Can you explain this answer?.
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