JEE Question > Differentiatewith respect to x.a)-1b)c)π/4...

Differentiate with respect to x.

- a)-1
- b)
- c)π/4 − x
- d)1

Correct answer is option 'A'. Can you explain this answer?

(cosx − sinx)/(cosx + sinx) = (1 − tanx)/(1 + tanx)

tan(A − B) = (tanA − tanB)/(1 + tanAtanB)

= tan(π/4−x)

putting this value in question.

tan^{−1} tan(π/4−x)

π/4 − x.

tan(A − B) = (tanA − tanB)/(1 + tanAtanB)

= tan(π/4−x)

putting this value in question.

tan

π/4 − x.

so d(π/4 − x)/dx = -1

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Differentiatewith respect to x.a)-1b)c)π/4 − xd)1Correct answer is option 'A'. Can you explain this answer? for JEE 2023 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Differentiatewith respect to x.a)-1b)c)π/4 − xd)1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2023 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Differentiatewith respect to x.a)-1b)c)π/4 − xd)1Correct answer is option 'A'. Can you explain this answer?.

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(cosx − sinx)/(cosx + sinx) = (1 − tanx)/(1 + tanx)tan(A − B) = (tanA − tanB)/(1 + tanAtanB)= tan(π/4−x)putting this value in question.tan−1 tan(π/4−x)π/4 − x.so d(π/4 − x)/dx = -1