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If log(2a-3b)=log a -log b, then a=
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If log(2a-3b)=log a -log b, then a=
Log(2a-3b)= log a -  log b
log (2a - 3b) = log (a/b) 
2a - 3b = a/b
b(2a - 3b) = a
2ab -  3b^2 = a
2ab -  a = 3b^2
a (2b -  a) = 3b^2
a = 3b^2 / (2b - a) 
Community Answer
If log(2a-3b)=log a -log b, then a=
Explanation: Solving for a given equation


We are given an equation log(2a-3b)=log a -log b, and we are required to solve for a. Here is how we can do it:


Step 1: Simplify the equation


We can simplify the equation using the following logarithmic identities:



  • log a - log b = log (a/b)

  • log x + log y = log (xy)



Using these identities, we can rewrite the equation as:



  • log(2a-3b) = log (a/b)

  • 2a-3b = a/b



Step 2: Rearrange the equation


We can rearrange the equation to isolate a on one side:



  • 2a - 3b = a/b

  • 2ab - 3b^2 = a

  • a = 3b^2 / (2b-1)



Step 3: Check for extraneous solutions


Since we took the logarithm of both sides of the original equation, we need to check if the solution we obtained is valid. If a or b is negative or zero, then the logarithm is undefined.


Step 4: Final answer


The final answer is:



  • a = 3b^2 / (2b-1), where b > 1/2 and b ≠ 0

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If log(2a-3b)=log a -log b, then a=
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