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Given an isosceles triangle, whose one angle is 120º and radius of its incircle is √3, then the area of the triangle in sq. units is
  • a)
    7+12√3
  • b)
    12+7√3
  • c)
    12-7√3
  • d)
    4+2√3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Given an isosceles triangle, whose one angle is 120º and radius o...
Let the angles be A,B,C
Given:∠A=120∘
and since it is an isosceles Triangle, other two angles must be equal 
We have B=C
    = √3(4 + 3 + 4√3)
    = 7√3 + 12
 
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Most Upvoted Answer
Given an isosceles triangle, whose one angle is 120º and radius o...
If we have an isosceles triangle with one angle measuring 120 degrees, we know that the other two angles are equal. Let's call these angles x.

Since the sum of the angles in a triangle is always 180 degrees, we can write the equation:

120 + x + x = 180

Simplifying, we have:

120 + 2x = 180

Subtracting 120 from both sides:

2x = 60

Dividing both sides by 2:

x = 30

So the other two angles in the isosceles triangle each measure 30 degrees.
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