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In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer?.

Solutions for In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In a series resonant R-L-C circuit, the voltage across R is 100 V and the value of R = 1000W. The capacitance of the capacitor is 2´10-6F; angular frequency of AC is 200 rad s-1. Then the P.D. across the inductance coil is ______.a)250 Vb)400 Vc)100 Vd)40 VCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.