The set S has elements of the form 2n, with n...
The set S has elements of the form 2n, with n taking on all natural number values. Let m be any element of S. If p is the number of real roots of the equation xm + 1 - x = 0, how many different values are possible for p?
The set S has elements of the form 2n, with n taking on all natural nu...
Let m - 2n for some natural number n.
Consider the equation,
xm+1- x = 0
x(xm - 1) = 0
x = 0 or xm = 1
m is even,
the possible real roots of the equation are, -1, 0 and 1.
Since p = 3 for all n and m, there is only one possible value of p. Answer: 1
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The set S has elements of the form 2n, with n taking on all natural number values. Let m be any element of S. If p is the number of real roots of the equation xm+ 1 - x = 0, how many different values are possible for p?Correct answer is '1'. Can you explain this answer?
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