All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
Class 12 Exam  >  Class 12 Questions  >  Two bulbs A and B are rated 100 W, 120 V and ... Start Learning for Free
SaveJoin the Discussion on the App
Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.​
  • a)
    0.08 A
  • b)
    0.0083 A
  • c)
    0.083 A
  • d)
    8 A
Correct answer is option 'C'. Can you explain this answer?
FREE This question is part of
Download PDF Attempt Test
Download PDF Attempt this Test
Verified Answer
Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively....
Bulb A,
PA=100w
VA=120v
We know that, P=VI
So, I=P/V=100w/120v=5/6A=0.83A
Bulb B,
PB=100w
VB=120v
We know that, P=VI
So, I=P/V=10w/120v=1/12A=0.083A
Bulb A will consume more energy than bulb B when they are connected in parallel.
 
View all questions of this test
Most Upvoted Answer
Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively....
To calculate the current through each bulb, we can use Ohm's Law and the formula for power.

1. Ohm's Law: Ohm's Law states that the current flowing through a conductor is directly proportional to the voltage across the conductor, and inversely proportional to the resistance of the conductor. Mathematically, it can be expressed as:

I = V/R

Where I is the current, V is the voltage, and R is the resistance.

2. Power formula: The power consumed by a device can be calculated using the formula:

P = IV

Where P is the power, I is the current, and V is the voltage.

Given information:
- Bulb A: Rated 100 W, 120 V
- Bulb B: Rated 10 W, 120 V
- Connected in series across a 120 V source

Since the bulbs are connected in series, the current passing through both bulbs will be the same.

Let's calculate the resistance of each bulb using the power formula:

- Bulb A: P = IV
100 W = I * 120 V
I = 100 W / 120 V
I = 0.833 A

- Bulb B: P = IV
10 W = I * 120 V
I = 10 W / 120 V
I = 0.0833 A

Since the resistances of the bulbs are different, the current passing through each bulb will be different. The bulb with higher resistance (Bulb B) will have a lower current, and the bulb with lower resistance (Bulb A) will have a higher current.

Therefore, the current through each bulb is as follows:
- Bulb A: 0.0833 A
- Bulb B: 0.0833 A

So, the correct answer is option C: 0.083 A.
< Previous Question Next Question >
Explore Courses for Class 12 exam

Similar Class 12 Doubts

Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.Manganin and Constantan are used for making the shunt of DC and AC ammeter respectively. What is multiplying power of the shunt?

Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.Materials used for making shunt of DC and AC ammeter are respectively

Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.Current through shunt is

Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer?
Question Description
Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer?.
Solutions for Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup