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Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.​
  • a)
    0.08 A
  • b)
    0.0083 A
  • c)
    0.083 A
  • d)
    8 A
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively....
In the bulb A -  
                     
                      ⇒ Volts = 120 v

                      ⇒ Power = 100 w

⇒In the bulb B-

                    ⇒ Volts = 120 v

                    ⇒ Power = 10 w


Now let us find the resistance of the two bulbs -


             ⇒ R = V^2/ P


Let us find the resistance for the bulb A-

             ⇒ Bulb A ( R ) =  120^2 / 100 =  144 ohm


             ⇒ Bulb B ( r ) =  120^2 / 10  = 1440 ohm



Now we got the resistance for both the bulbs.

To find the series combination , we need to use the below formula to find out it -


⇒ R = R₁ + R₂ =
 
      =  144 + 1440

      = 1584 ohm is the resistance in series combination.



So 10 watts bulb consume more energy because uses less power and also the amount o current flowing is less . Remember the formula -  P=I x E. 
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Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively....
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Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively....
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Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.Materials used for making shunt of DC and AC ammeter are respectively

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Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.​a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'A'. Can you explain this answer?
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Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.​a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.​a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bulbs A and B are rated 100 W, 120 V and 10 W, 120 V respectively. They are connected across a 120 V source in series. Calculate the current through each bulb.​a)0.08 Ab)0.0083 Ac)0.083 Ad)8 ACorrect answer is option 'A'. Can you explain this answer?.
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