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The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer?.

Solutions for The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The equation of circumcircle of an equilateral triangle is x2+ y2+ 2gx + 2fy + c = 0 and one vertex of the triangle is (1, 1). The equation of incircle of the triangle isa)4 (x2+ y2) = g2+ f2b)4 (x2+ y2) + 8gx + 8fy = (1 – g) (1 + 3g) + (1 – f) (1 + 3f)c)4 (x2+ y2) + 8gx + 8fy = g2+ f2d)none of theseCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.