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Rampal started at 3 pm from A for B on a straight road. He covered half the distance at S1 km/hr and then increased his speed to S2 km/hr for the remaining distance. At the same time, Arvind started from A at a speed S2 km/hr and travelled in a straight line to C, then he travelled from C to B in a straight line, at the same speed. D is on the straight road joining A and B. Road joining C and D is perpendicular to that joining A and B, such that AD = BD = CD = 50 km. If both took equal time to reach point B, then find S2/S1.
  • a)
    2√2 - 1
  • b)
    2√2 + 1
  • c)
    √2 - 1
  • d)
    √2 + 1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Rampal started at 3 pm from A for B on a straight road. He covered hal...
Using Pythagoras theorem
AC ≡ CB ≡ 50√2
Time taken by Rampal to cover the distance along AB

Time taken by Arvind to cover the distance (AC + CB)

As both took equal time to reach B,


Hence, option 1.
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Most Upvoted Answer
Rampal started at 3 pm from A for B on a straight road. He covered hal...
Let the total distance between A and B be D km.

Rampal covers half the distance at speed S1 km/hr, so he covers D/2 km in D/2S1 hours.

For the remaining distance, Rampal increases his speed to S2 km/hr. Let the time taken to cover this distance be t hours.

So, the remaining distance covered by Rampal is (D/2) - (S2 * t).

Since Arvind and Rampal take the same time to reach point B, the time taken by Arvind to reach point C (D/2 km away from A) is also D/2S1 hours.

The speed of Arvind is S2 km/hr, and the distance covered by Arvind to reach point C is D/2 km. So, the time taken by Arvind to reach point C is (D/2) / S2 hours.

Since AD = BD = CD = 50 km, the distance covered by Arvind from C to B is also 50 km.

The speed of Arvind is S2 km/hr, and the distance covered by Arvind from C to B is 50 km. So, the time taken by Arvind to cover this distance is 50 / S2 hours.

Since both Rampal and Arvind take the same time to reach point B, we can equate the times:

D/2S1 + (D/2 - S2t) / S2 = (D/2) / S2 + 50 / S2

D/2S1 + D/2S2 - t = D/2S2 + 50 / S2

D/2S1 = 50 / S2

S2 / S1 = 50 / (D/2)

S2 / S1 = 100 / D

Therefore, S2 / S1 = 100 / D.

Since the value of D is not given in the question, we cannot find the exact value of S2 / S1. So, the answer cannot be determined with the given information.
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Rampal started at 3 pm from A for B on a straight road. He covered half the distance at S1 km/hr and then increased his speed to S2 km/hr for the remaining distance. At the same time, Arvind started from A at a speed S2 km/hr and travelled in a straight line to C, then he travelled from C to B in a straight line, at the same speed. D is on the straight road joining A and B. Road joining C and D is perpendicular to that joining A and B, such that AD = BD = CD = 50 km. If both took equal time to reach point B, then find S2/S1.a)2√2 - 1b)2√2 + 1c)√2 - 1d)√2 + 1Correct answer is option 'A'. Can you explain this answer?
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Rampal started at 3 pm from A for B on a straight road. He covered half the distance at S1 km/hr and then increased his speed to S2 km/hr for the remaining distance. At the same time, Arvind started from A at a speed S2 km/hr and travelled in a straight line to C, then he travelled from C to B in a straight line, at the same speed. D is on the straight road joining A and B. Road joining C and D is perpendicular to that joining A and B, such that AD = BD = CD = 50 km. If both took equal time to reach point B, then find S2/S1.a)2√2 - 1b)2√2 + 1c)√2 - 1d)√2 + 1Correct answer is option 'A'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Rampal started at 3 pm from A for B on a straight road. He covered half the distance at S1 km/hr and then increased his speed to S2 km/hr for the remaining distance. At the same time, Arvind started from A at a speed S2 km/hr and travelled in a straight line to C, then he travelled from C to B in a straight line, at the same speed. D is on the straight road joining A and B. Road joining C and D is perpendicular to that joining A and B, such that AD = BD = CD = 50 km. If both took equal time to reach point B, then find S2/S1.a)2√2 - 1b)2√2 + 1c)√2 - 1d)√2 + 1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Rampal started at 3 pm from A for B on a straight road. He covered half the distance at S1 km/hr and then increased his speed to S2 km/hr for the remaining distance. At the same time, Arvind started from A at a speed S2 km/hr and travelled in a straight line to C, then he travelled from C to B in a straight line, at the same speed. D is on the straight road joining A and B. Road joining C and D is perpendicular to that joining A and B, such that AD = BD = CD = 50 km. If both took equal time to reach point B, then find S2/S1.a)2√2 - 1b)2√2 + 1c)√2 - 1d)√2 + 1Correct answer is option 'A'. Can you explain this answer?.
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