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The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 250C are –400 kJ/mol,
–300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at
250C is
  • a)
    +2900 kJ
  • b)
    – 2900 kJ
  • c)
    –16.11 kJ
  • d)
    +16.11 kJ
Correct answer is option 'C'. Can you explain this answer?
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The standard enthalpies of formation of CO2(g), H2O(l), and glucose(s) at 25°C are:

- CO2(g): -393.5 kJ/mol
- H2O(l): -285.8 kJ/mol
- Glucose(s): -1273.3 kJ/mol
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The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 250C are –400 kJ/mol,–300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at250C isa)+2900 kJb)– 2900 kJc)–16.11 kJd)+16.11 kJCorrect answer is option 'C'. Can you explain this answer?
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The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 250C are –400 kJ/mol,–300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at250C isa)+2900 kJb)– 2900 kJc)–16.11 kJd)+16.11 kJCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 250C are –400 kJ/mol,–300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at250C isa)+2900 kJb)– 2900 kJc)–16.11 kJd)+16.11 kJCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 250C are –400 kJ/mol,–300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at250C isa)+2900 kJb)– 2900 kJc)–16.11 kJd)+16.11 kJCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 250C are –400 kJ/mol,–300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at250C isa)+2900 kJb)– 2900 kJc)–16.11 kJd)+16.11 kJCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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