Question Description
The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer?.

Solutions for The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The standard enthalpies of for mation of CO2(g), H2O(l) and glucose (s) at 25°C are - 400 kJ / mol, - 300 kJ / mol and - 1300 kJ / mol, respectively .The standard enthalpy of combustion per gram Of glucose at 25°C is(2013 Adv., Single Option Correct)a)+ 2900 kJb)- 2900 kJc)- 16.11 kJd)+ 16.11 kJCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.