A man weighing 70 kg carries a weight of 10 kg on the top of a tower 1...
Calculation of Work Done by a Man Carrying a Weight on Top of a Tower
Introduction: In physics, work is defined as the product of force and displacement. When a force is applied to an object, the object is said to have done work if it moves in the direction of the force. In this problem, we have to calculate the work done by a man who carries a weight on top of a tower.
Given Data:
- Weight of a man = 70 kg
- Weight of the object = 10 kg
- Height of the tower = 100 m
Calculations:
- Work done by the man can be calculated as the product of force and displacement.
- The force required to lift the object can be calculated as the weight of the object multiplied by the acceleration due to gravity.
- The acceleration due to gravity is 9.8 m/s².
- Therefore, force required to lift the object = 10 kg x 9.8 m/s² = 98 N.
- The displacement of the object is the height of the tower, which is 100 m.
- Therefore, work done by the man = force x displacement = 98 N x 100 m = 9800 J.
Conclusion:
- The work done by the man carrying a weight on top of a tower is 9800 J.
- This means that the man has done 9800 J of work to lift the weight of 10 kg to the top of the tower.
A man weighing 70 kg carries a weight of 10 kg on the top of a tower 1...
Weight of the man=70kg,
weight of the thing carried= 10kg,
height of the tower=100m,
mass=10+70=80,
height =100,
work done=mgh=80×10×100=80000j.