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1. The velocity distribution for flow over a flat plate is given by u = 3/2y - y^3/2 , Where u is the point velocity in meter per second at a distance y meter above the plate. Determine the shear stress at y = 9 cm. Assume dynamic viscosity as 8 poise .?
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1. The velocity distribution for flow over a flat plate is given by u ...
Shear Stress Calculation for Flow over a Flat Plate

Given:
- Velocity distribution: u = (3/2)y - y^(3/2)
- Distance from the plate: y = 9 cm
- Dynamic viscosity: 8 poise

Shear Stress Formula:
The shear stress (τ) can be calculated using the formula:

τ = μ * du/dy

where:
- τ is the shear stress
- μ is the dynamic viscosity
- du/dy is the derivative of the velocity distribution with respect to y

To determine the shear stress at y = 9 cm, we need to calculate the derivative du/dy first.

Derivative Calculation:
The velocity distribution equation is u = (3/2)y - y^(3/2). To find du/dy, we differentiate this equation with respect to y.

du/dy = d/dy[(3/2)y - y^(3/2)]

Applying the power rule of differentiation, we get:

du/dy = (3/2) - (3/2)(3/2)y^(-1/2)

Simplifying further, we have:

du/dy = (3/2) - (9/4)y^(-1/2)

Shear Stress Calculation:
Now that we have the derivative du/dy, we can calculate the shear stress at y = 9 cm using the shear stress formula.

τ = μ * du/dy

Plugging in the given values:

τ = 8 * [(3/2) - (9/4)(9^(-1/2))]

Calculating further:

τ = 8 * [(3/2) - (9/4)(1/3)]

τ = 8 * [(3/2) - (3/4)]

τ = 8 * [(6/4) - (3/4)]

τ = 8 * (3/4)

τ = 6 poise

Result:
The shear stress at y = 9 cm is 6 poise.
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1. The velocity distribution for flow over a flat plate is given by u = 3/2y - y^3/2 , Where u is the point velocity in meter per second at a distance y meter above the plate. Determine the shear stress at y = 9 cm. Assume dynamic viscosity as 8 poise .?
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