Mechanical Engineering Exam > Mechanical Engineering Questions > If the velocity distribution over a plate is ...
Start Learning for Free
If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.?
Most Upvoted Answer
If the velocity distribution over a plate is given by u= 2/3 * y - y ^...
Given:
Velocity distribution, u = 2/3*y - y^2
Dynamic viscosity of fluid, μ = 8.63 poise
Distance above the plate, y = 0 and y = 0.15 m
Shear Stress Calculation:
To calculate the shear stress, we need to use the formula:
τ = μ*(du/dy)
where τ is the shear stress, μ is the dynamic viscosity of the fluid, and du/dy is the velocity gradient.
Shear Stress at y = 0:
At y = 0, the velocity distribution becomes:
u = 2/3*0 - 0^2 = 0
Therefore, the velocity gradient, du/dy = 0
And, the shear stress, τ = μ*(du/dy) = 0
Hence, the shear stress at y = 0 is zero.
Shear Stress at y = 0.15:
At y = 0.15 m, the velocity distribution becomes:
u = 2/3*0.15 - 0.15^2 = 0.0225 m/s
To calculate the velocity gradient, we differentiate the velocity distribution with respect to y:
du/dy = 2/3 - 2*y
So, at y = 0.15 m, du/dy = 2/3 - 2*0.15 = 0.3 1/s
Therefore, the shear stress, τ = μ*(du/dy) = 8.63*0.3 = 2.589 Pa
Hence, the shear stress at y = 0.15 m is 2.589 Pa.
Conclusion:
The shear stress at y = 0 is zero, and the shear stress at y = 0.15 m is 2.589 Pa. The calculation is based on the given velocity distribution and dynamic viscosity of the fluid.
Velocity distribution, u = 2/3*y - y^2
Dynamic viscosity of fluid, μ = 8.63 poise
Distance above the plate, y = 0 and y = 0.15 m
Shear Stress Calculation:
To calculate the shear stress, we need to use the formula:
τ = μ*(du/dy)
where τ is the shear stress, μ is the dynamic viscosity of the fluid, and du/dy is the velocity gradient.
Shear Stress at y = 0:
At y = 0, the velocity distribution becomes:
u = 2/3*0 - 0^2 = 0
Therefore, the velocity gradient, du/dy = 0
And, the shear stress, τ = μ*(du/dy) = 0
Hence, the shear stress at y = 0 is zero.
Shear Stress at y = 0.15:
At y = 0.15 m, the velocity distribution becomes:
u = 2/3*0.15 - 0.15^2 = 0.0225 m/s
To calculate the velocity gradient, we differentiate the velocity distribution with respect to y:
du/dy = 2/3 - 2*y
So, at y = 0.15 m, du/dy = 2/3 - 2*0.15 = 0.3 1/s
Therefore, the shear stress, τ = μ*(du/dy) = 8.63*0.3 = 2.589 Pa
Hence, the shear stress at y = 0.15 m is 2.589 Pa.
Conclusion:
The shear stress at y = 0 is zero, and the shear stress at y = 0.15 m is 2.589 Pa. The calculation is based on the given velocity distribution and dynamic viscosity of the fluid.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.?
Question Description
If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.?.
If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.?.
Solutions for If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? defined & explained in the simplest way possible. Besides giving the explanation of
If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.?, a detailed solution for If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? has been provided alongside types of If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? theory, EduRev gives you an
ample number of questions to practice If the velocity distribution over a plate is given by u= 2/3 * y - y ^ 2 in which u is the velocity in m/s at a distance of y meter above the plate, determine the shear stress at y = 0 and y=0.15.Take dynamic viscosity of fluid as 8.63 poise.? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup