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1. The velocity distribution for flow over a flat plate is given by u = 3/2y - y^3/2 , Where u is the point velocity in meter per second at a distance y meter above the plate. Determine the shear stress at y = 9 cm. Assume dynamic viscosity as 8 poise?
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1. The velocity distribution for flow over a flat plate is given by u ...
Solution:

Given,
u = 3/2y - y^3/2
y = 9 cm = 0.09 m
Dynamic viscosity, μ = 8 poise = 0.8 Ns/m^2

To find: Shear stress at y = 9 cm.

Calculation:

Velocity gradient, du/dy = 3/2 - 3/2y^(1/2)
= 3/2 - 3/2(0.09)^(1/2)
= 1.2638 s^-1

Shear stress, τ = μ (du/dy)
= 0.8 x 1.2638
= 1.011 N/m^2

Therefore, the shear stress at y = 9 cm is 1.011 N/m^2.
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1. The velocity distribution for flow over a flat plate is given by u = 3/2y - y^3/2 , Where u is the point velocity in meter per second at a distance y meter above the plate. Determine the shear stress at y = 9 cm. Assume dynamic viscosity as 8 poise?
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