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If an unbiased coin is tossed twice, the probability of obtaining at least one tail is
- a)0.25
- b)0.50
- c)0.75
- d)1.00
Correct answer is option 'C'. Can you explain this answer?
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If an unbiased coin is tossed twice, the probability of obtaining at l...
Solution:
When an unbiased coin is tossed, the possible outcomes are heads (H) and tails (T). The probability of getting a head or a tail in one toss is 1/2.
Now, when the coin is tossed twice, there are four possible outcomes: HH, HT, TH, and TT.
Out of these four outcomes, only one outcome (HH) does not have a tail. Therefore, the probability of getting at least one tail is:
P(at least one tail) = 1 - P(no tail)
To calculate P(no tail), we need to find the probability of getting a head in both tosses, which is:
P(no tail) = P(HH) = 1/2 x 1/2 = 1/4
Therefore,
P(at least one tail) = 1 - P(no tail) = 1 - 1/4 = 3/4 = 0.75
Hence, the correct answer is option C, 0.75.
When an unbiased coin is tossed, the possible outcomes are heads (H) and tails (T). The probability of getting a head or a tail in one toss is 1/2.
Now, when the coin is tossed twice, there are four possible outcomes: HH, HT, TH, and TT.
Out of these four outcomes, only one outcome (HH) does not have a tail. Therefore, the probability of getting at least one tail is:
P(at least one tail) = 1 - P(no tail)
To calculate P(no tail), we need to find the probability of getting a head in both tosses, which is:
P(no tail) = P(HH) = 1/2 x 1/2 = 1/4
Therefore,
P(at least one tail) = 1 - P(no tail) = 1 - 1/4 = 3/4 = 0.75
Hence, the correct answer is option C, 0.75.
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If an unbiased coin is tossed twice, the probability of obtaining at least one tail isa)0.25b)0.50c)0.75d)1.00Correct answer is option 'C'. Can you explain this answer?
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