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A sum of 44000 is divided into 3 parts such that the corresponding interest earned after 2 years , 3 years and 6 years may be equal at the rate of simple interest are 6% p.a,8% p.a & 6% p.a respectively. Then the smallest part of the sum will be:?
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A sum of 44000 is divided into 3 parts such that the corresponding int...
, and 10% p.a. What are the three parts?
Let the three parts be x, y, and z.
According to the given information, the interest earned on x after 2 years at 6% p.a. is equal to the interest earned on y after 3 years at 8% p.a., which is also equal to the interest earned on z after 6 years at 10% p.a.
Using the formula for simple interest, we can write the following equations:
Interest on x after 2 years = (x * 6 * 2) / 100
Interest on y after 3 years = (y * 8 * 3) / 100
Interest on z after 6 years = (z * 10 * 6) / 100
Since the interest earned on x after 2 years, y after 3 years, and z after 6 years are equal, we can equate them:
(x * 6 * 2) / 100 = (y * 8 * 3) / 100 = (z * 10 * 6) / 100
Simplifying the equation, we get:
12x = 24y = 60z
Since the sum of the three parts is 44000, we can write another equation:
x + y + z = 44000
Using the equation 12x = 24y = 60z, we can solve for x in terms of y:
12x = 24y
x = 2y
Substituting x = 2y in the equation x + y + z = 44000, we get:
2y + y + z = 44000
3y + z = 44000
Now, substituting x = 2y and z = 12x/5 in the equation (x * 6 * 2) / 100 = (y * 8 * 3) / 100 = (z * 10 * 6) / 100, we get:
(2y * 6 * 2) / 100 = (y * 8 * 3) / 100 = (12x/5 * 10 * 6) / 100
Simplifying the equation, we get:
24y = 24y = 72x/5
24y = 72x/5
120y = 72x
5y = 3x
Substituting 5y = 3x in the equation 3y + z = 44000, we get:
3(5y) + z = 44000
15y + z = 44000
Now, we have two equations:
3y + z = 44000
15y + z = 44000
Subtracting the first equation from the second equation, we get:
15y - 3y + z - z = 44000 - 44000
12y = 0
y = 0
Substituting y = 0 in the equation x + y + z = 44000, we get:
x + 0 + z = 44000
x + z = 44000
Since y = 0, x + z = 44000, and 5y = 3x, we can conclude that
Let the three parts be x, y, and z.
According to the given information, the interest earned on x after 2 years at 6% p.a. is equal to the interest earned on y after 3 years at 8% p.a., which is also equal to the interest earned on z after 6 years at 10% p.a.
Using the formula for simple interest, we can write the following equations:
Interest on x after 2 years = (x * 6 * 2) / 100
Interest on y after 3 years = (y * 8 * 3) / 100
Interest on z after 6 years = (z * 10 * 6) / 100
Since the interest earned on x after 2 years, y after 3 years, and z after 6 years are equal, we can equate them:
(x * 6 * 2) / 100 = (y * 8 * 3) / 100 = (z * 10 * 6) / 100
Simplifying the equation, we get:
12x = 24y = 60z
Since the sum of the three parts is 44000, we can write another equation:
x + y + z = 44000
Using the equation 12x = 24y = 60z, we can solve for x in terms of y:
12x = 24y
x = 2y
Substituting x = 2y in the equation x + y + z = 44000, we get:
2y + y + z = 44000
3y + z = 44000
Now, substituting x = 2y and z = 12x/5 in the equation (x * 6 * 2) / 100 = (y * 8 * 3) / 100 = (z * 10 * 6) / 100, we get:
(2y * 6 * 2) / 100 = (y * 8 * 3) / 100 = (12x/5 * 10 * 6) / 100
Simplifying the equation, we get:
24y = 24y = 72x/5
24y = 72x/5
120y = 72x
5y = 3x
Substituting 5y = 3x in the equation 3y + z = 44000, we get:
3(5y) + z = 44000
15y + z = 44000
Now, we have two equations:
3y + z = 44000
15y + z = 44000
Subtracting the first equation from the second equation, we get:
15y - 3y + z - z = 44000 - 44000
12y = 0
y = 0
Substituting y = 0 in the equation x + y + z = 44000, we get:
x + 0 + z = 44000
x + z = 44000
Since y = 0, x + z = 44000, and 5y = 3x, we can conclude that
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A sum of 44000 is divided into 3 parts such that the corresponding interest earned after 2 years , 3 years and 6 years may be equal at the rate of simple interest are 6% p.a,8% p.a & 6% p.a respectively. Then the smallest part of the sum will be:?
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A sum of 44000 is divided into 3 parts such that the corresponding interest earned after 2 years , 3 years and 6 years may be equal at the rate of simple interest are 6% p.a,8% p.a & 6% p.a respectively. Then the smallest part of the sum will be:? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about A sum of 44000 is divided into 3 parts such that the corresponding interest earned after 2 years , 3 years and 6 years may be equal at the rate of simple interest are 6% p.a,8% p.a & 6% p.a respectively. Then the smallest part of the sum will be:? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sum of 44000 is divided into 3 parts such that the corresponding interest earned after 2 years , 3 years and 6 years may be equal at the rate of simple interest are 6% p.a,8% p.a & 6% p.a respectively. Then the smallest part of the sum will be:?.
A sum of 44000 is divided into 3 parts such that the corresponding interest earned after 2 years , 3 years and 6 years may be equal at the rate of simple interest are 6% p.a,8% p.a & 6% p.a respectively. Then the smallest part of the sum will be:? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about A sum of 44000 is divided into 3 parts such that the corresponding interest earned after 2 years , 3 years and 6 years may be equal at the rate of simple interest are 6% p.a,8% p.a & 6% p.a respectively. Then the smallest part of the sum will be:? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sum of 44000 is divided into 3 parts such that the corresponding interest earned after 2 years , 3 years and 6 years may be equal at the rate of simple interest are 6% p.a,8% p.a & 6% p.a respectively. Then the smallest part of the sum will be:?.
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