Problem: What least number must be subtracted from 543 to get a number exactly divisible by 8?

Solution:

To find the least number that must be subtracted from 543 to make it divisible by 8, follow the steps below:

1. Determine the remainder when 543 is divided by 8.

- Divide 543 by 8: 543 ÷ 8 = 67 with a remainder of 7.

- The remainder is 7, which means that 543 is 7 more than a multiple of 8.

2. Find the number that, when subtracted from 543, will make it a multiple of 8.

- To make 543 a multiple of 8, we need to subtract 7 from it, since 7 is the amount that it is above the nearest multiple of 8.

3. Check the result.

- Subtract 7 from 543: 543 - 7 = 536

- Divide 536 by 8: 536 ÷ 8 = 67 with no remainder.

- Therefore, 536 is divisible by 8 and the answer is 7.

Answer: The least number that must be subtracted from 543 to get a number exactly divisible by 8 is 7.

When 543 is divided by 8, the remainder comes out be 7.



If 7 is subtracted from 543 , then we get 536 which is exactly divisible by 8.




So, the least no. to be subtracted is 7.