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The increasing order of stability of the following free radicals is .
  • a)
    (CH3​)2​CH˙<(CH3​)3​C˙<(C6​H5​)2​CH˙<(C6​H5​)3​C˙
  • b)
    (C6​H5​)3​C˙<(C6​H5​)2​CH˙<(CH3​)3​C˙<(CH3​)2​CH˙
  • c)
    (C6​H5​)2​CH˙<(C6​H5​)3​C˙<(CH3​)3​C˙<(CH3​)2​CH˙
  • d)
    (CH3​)2​CH˙<(CH3​)3​C˙<(C6​H5​)3​C˙<(C6​H5​)2​CH˙
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The increasing order of stability of the following free radicals is .a...
Radical is stabilized by α hydrogen. More the α-hydrogen more will be hyperconjugation more will be radical stabilization resonance. 
Resonance is also a good stabilizing factor and is given preference than hyperconjugation.
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Most Upvoted Answer
The increasing order of stability of the following free radicals is .a...
The increasing order of stability of the given free radicals is:

a) (CH3)2CH

In this radical, there are two methyl groups attached to the central carbon atom. The presence of these methyl groups increases the electron density around the central carbon atom, making it more stable. This is due to the inductive effect, where the methyl groups donate electron density through the sigma bonds to the central carbon atom. As a result, the central carbon atom is better able to stabilize the unpaired electron in the radical.

Therefore, (CH3)2CH is more stable than other radicals without any electron-donating groups.
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