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Find the differential coefficient y = (sec 5x)5x 
  • a)
    log ( sec 5x) + 5x log (tan 5x)
  • b)
    5(sec 5x)5x [log (sec 5x) + 5x tan 5x ]
  • c)
    (sec 5x)5x [log( sec 5x) + 5x log (tan 5x)]
  • d)
    log (sec 5x) + 5x tan 5x
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Find the differential coefficient y = (sec 5x)5xa)log ( sec 5x) + 5x l...
Explanation:

Given: y = (sec 5x)^5x

Step 1: Apply the chain rule to find the differential coefficient of y with respect to x.

Step 2: Differentiate the function (sec 5x)^5x using the chain rule.

Step 3: Apply the chain rule to differentiate (sec 5x)^5x.

Step 4: The differential coefficient of y is given by 5(sec 5x)^5x[log(sec 5x) + 5x tan 5x].
Therefore, the correct answer is option B - 5(sec 5x)^5x[log(sec 5x) + 5x tan 5x].
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Community Answer
Find the differential coefficient y = (sec 5x)5xa)log ( sec 5x) + 5x l...
Take log of both sides then differentiate with respect to x. then replace the value of y in the equation
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Find the differential coefficient y = (sec 5x)5xa)log ( sec 5x) + 5x log (tan 5x)b)5(sec 5x)5x[log (sec 5x) + 5x tan 5x ]c)(sec 5x)5x[log( sec 5x) + 5x log (tan 5x)]d)log (sec 5x) + 5x tan 5xCorrect answer is option 'B'. Can you explain this answer?
Question Description
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