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Triangle ABC is isosceles with AB=AC=7.5cm and bc=9 cm. the height ad from a to bc is 6cm.find the area of triangle abc.what will be the height from c to ab ie., ce
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Triangle ABC is isosceles with AB=AC=7.5cm and bc=9 cm. the height ad ...
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Triangle ABC is isosceles with AB=AC=7.5cm and bc=9 cm. the height ad ...
Given:
- Triangle ABC is isosceles with AB=AC=7.5cm and BC=9cm.
- The height AD from A to BC is 6cm.

To find:
- The area of triangle ABC.
- The height CE from C to AB.

Solution:

1. Finding the Area of Triangle ABC:
To find the area of triangle ABC, we can use the formula: Area = (base * height) / 2.

In this case, the base of the triangle is BC, which is given as 9cm. And the height of the triangle is AD, which is given as 6cm.

Using the formula, we can calculate the area as follows:
Area = (9 * 6) / 2
Area = 54 / 2
Area = 27 square cm

Therefore, the area of triangle ABC is 27 square cm.

2. Finding the Height CE:
To find the height CE, we can use the property of isosceles triangles.

In an isosceles triangle, the height from the vertex angle bisects the base. This means that the height CE will divide the base AB into two equal parts.

Since AB is isosceles with AB=AC=7.5cm, the height CE will divide AB into two equal parts of length 7.5cm/2 = 3.75cm.

Therefore, the height CE from C to AB is 3.75cm.

Summary:
- The area of triangle ABC is 27 square cm.
- The height CE from C to AB is 3.75cm.
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Triangle ABC is isosceles with AB=AC=7.5cm and bc=9 cm. the height ad from a to bc is 6cm.find the area of triangle abc.what will be the height from c to ab ie., ce
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