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A 50 Ω resistance is connected to a battery of 5V. A galvanometer of resistance 100 Ω is to be used as an ammeter to measure current through the resistance, for this a resistance rs is connected to the galvanometer. Which of the following connections should be employed if the measured current is within 1% of the current without the ammeter in the circuit ?
- a)rs = 0.5 Ω in parallel with the galvanometer
- b)rs = 0.5 Ω in series with the galvanometer
- c)rs = 1 Ω in series with galvanometer
- d)rs=1 Ω in parallel with galvanometer
Correct answer is option 'A'. Can you explain this answer?
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A 50 resistance is connected to a battery of 5V. A galvanometer of re...
Explanation:
To measure the current through the resistance, a galvanometer is used as an ammeter. The resistance of the galvanometer is 100 ohms. To measure the current without the ammeter in the circuit, the current through the resistance is given by Ohm's law as follows:
I = V / R = 5 / 50 = 0.1 A
To measure the current through the resistance with the ammeter in the circuit, we need to use a shunt resistance rs to reduce the current passing through the galvanometer. The total current in the circuit is given by:
I = V / (R + rs + Rg)
where Rg is the resistance of the galvanometer, which is 100 ohms. The current passing through the galvanometer is given by:
Ig = V / (R + Rg)
The current passing through the shunt resistance rs is given by:
Is = V / rs
To ensure that the measured current is within 1% of the current without the ammeter in the circuit, we need to choose the value of rs such that the current passing through the galvanometer is within 1% of the current without the ammeter in the circuit. This means that:
Ig / I = (V / (R + Rg)) / (V / (R + rs + Rg)) = (R + rs + Rg) / (R + Rg) < />
Simplifying the above equation, we get:
rs < />
This means that the value of rs should be less than 1 ohm. Therefore, option A is correct, as rs = 0.5 ohms is less than 1 ohm and will ensure that the measured current is within 1% of the current without the ammeter in the circuit.
To measure the current through the resistance, a galvanometer is used as an ammeter. The resistance of the galvanometer is 100 ohms. To measure the current without the ammeter in the circuit, the current through the resistance is given by Ohm's law as follows:
I = V / R = 5 / 50 = 0.1 A
To measure the current through the resistance with the ammeter in the circuit, we need to use a shunt resistance rs to reduce the current passing through the galvanometer. The total current in the circuit is given by:
I = V / (R + rs + Rg)
where Rg is the resistance of the galvanometer, which is 100 ohms. The current passing through the galvanometer is given by:
Ig = V / (R + Rg)
The current passing through the shunt resistance rs is given by:
Is = V / rs
To ensure that the measured current is within 1% of the current without the ammeter in the circuit, we need to choose the value of rs such that the current passing through the galvanometer is within 1% of the current without the ammeter in the circuit. This means that:
Ig / I = (V / (R + Rg)) / (V / (R + rs + Rg)) = (R + rs + Rg) / (R + Rg) < />
Simplifying the above equation, we get:
rs < />
This means that the value of rs should be less than 1 ohm. Therefore, option A is correct, as rs = 0.5 ohms is less than 1 ohm and will ensure that the measured current is within 1% of the current without the ammeter in the circuit.
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A 50 resistance is connected to a battery of 5V. A galvanometer of resistance 100 is to be used as an ammeter to measure current through the resistance, for this a resistance rs is connected to the galvanometer. Which of the following connections should be employed if the measured current is within 1% of the current without the ammeter in the circuit ?a)rs = 0.5 in parallel with the galvanometerb)rs = 0.5 in series with the galvanometerc)rs = 1 in series with galvanometerd)rs=1 in parallel with galvanometerCorrect answer is option 'A'. Can you explain this answer?
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A 50 resistance is connected to a battery of 5V. A galvanometer of resistance 100 is to be used as an ammeter to measure current through the resistance, for this a resistance rs is connected to the galvanometer. Which of the following connections should be employed if the measured current is within 1% of the current without the ammeter in the circuit ?a)rs = 0.5 in parallel with the galvanometerb)rs = 0.5 in series with the galvanometerc)rs = 1 in series with galvanometerd)rs=1 in parallel with galvanometerCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 50 resistance is connected to a battery of 5V. A galvanometer of resistance 100 is to be used as an ammeter to measure current through the resistance, for this a resistance rs is connected to the galvanometer. Which of the following connections should be employed if the measured current is within 1% of the current without the ammeter in the circuit ?a)rs = 0.5 in parallel with the galvanometerb)rs = 0.5 in series with the galvanometerc)rs = 1 in series with galvanometerd)rs=1 in parallel with galvanometerCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 resistance is connected to a battery of 5V. A galvanometer of resistance 100 is to be used as an ammeter to measure current through the resistance, for this a resistance rs is connected to the galvanometer. Which of the following connections should be employed if the measured current is within 1% of the current without the ammeter in the circuit ?a)rs = 0.5 in parallel with the galvanometerb)rs = 0.5 in series with the galvanometerc)rs = 1 in series with galvanometerd)rs=1 in parallel with galvanometerCorrect answer is option 'A'. Can you explain this answer?.
A 50 resistance is connected to a battery of 5V. A galvanometer of resistance 100 is to be used as an ammeter to measure current through the resistance, for this a resistance rs is connected to the galvanometer. Which of the following connections should be employed if the measured current is within 1% of the current without the ammeter in the circuit ?a)rs = 0.5 in parallel with the galvanometerb)rs = 0.5 in series with the galvanometerc)rs = 1 in series with galvanometerd)rs=1 in parallel with galvanometerCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 50 resistance is connected to a battery of 5V. A galvanometer of resistance 100 is to be used as an ammeter to measure current through the resistance, for this a resistance rs is connected to the galvanometer. Which of the following connections should be employed if the measured current is within 1% of the current without the ammeter in the circuit ?a)rs = 0.5 in parallel with the galvanometerb)rs = 0.5 in series with the galvanometerc)rs = 1 in series with galvanometerd)rs=1 in parallel with galvanometerCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 resistance is connected to a battery of 5V. A galvanometer of resistance 100 is to be used as an ammeter to measure current through the resistance, for this a resistance rs is connected to the galvanometer. Which of the following connections should be employed if the measured current is within 1% of the current without the ammeter in the circuit ?a)rs = 0.5 in parallel with the galvanometerb)rs = 0.5 in series with the galvanometerc)rs = 1 in series with galvanometerd)rs=1 in parallel with galvanometerCorrect answer is option 'A'. Can you explain this answer?.
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