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To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angle θ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :
- a)2S (R+G)=RG
- b)S (R+G)=RG
- c)2S=G
- d)2G=S
Correct answer is option 'B'. Can you explain this answer?
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To know the resistance G of a galvanometer by half deflection method, ...
Θ. The resistance of the galvanometer is then connected in series with a resistance box of resistance R' and the same battery is used to deflect the galvanometer by angle θ/2. Let I be the current through the galvanometer when it is deflected by angle θ and I' be the current through the galvanometer when it is deflected by angle θ/2.
Using Kirchhoff's laws, we can write:
VE = IR + I(R' + G) (1) (when galvanometer is deflected by angle θ)
VE = I'R + I'(R' + G) (2) (when galvanometer is deflected by angle θ/2)
Dividing equation (2) by equation (1), we get:
I'/I = (R + R' + G)/(R + R')
Since I is the current through the galvanometer when it is deflected by angle θ, we can assume that the galvanometer is at full scale deflection in this case. Therefore, the current I is given by:
I = VE/(R + G)
Substituting this value of I in the above equation, we get:
I'/VE = (R + R' + G)/(R + G)
Solving for G, we get:
G = (R + R')[(I'/VE) - 1]
Therefore, to know the resistance G of a galvanometer by half deflection method, we need to measure the current I' through the galvanometer when it is deflected by angle θ/2, the emf VE of the battery, and the resistances R and R' of the battery and resistance box respectively.
Using Kirchhoff's laws, we can write:
VE = IR + I(R' + G) (1) (when galvanometer is deflected by angle θ)
VE = I'R + I'(R' + G) (2) (when galvanometer is deflected by angle θ/2)
Dividing equation (2) by equation (1), we get:
I'/I = (R + R' + G)/(R + R')
Since I is the current through the galvanometer when it is deflected by angle θ, we can assume that the galvanometer is at full scale deflection in this case. Therefore, the current I is given by:
I = VE/(R + G)
Substituting this value of I in the above equation, we get:
I'/VE = (R + R' + G)/(R + G)
Solving for G, we get:
G = (R + R')[(I'/VE) - 1]
Therefore, to know the resistance G of a galvanometer by half deflection method, we need to measure the current I' through the galvanometer when it is deflected by angle θ/2, the emf VE of the battery, and the resistances R and R' of the battery and resistance box respectively.
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To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angleθ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :a)2S (R+G)=RGb)S (R+G)=RGc)2S=Gd)2G=SCorrect answer is option 'B'. Can you explain this answer?
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To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angleθ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :a)2S (R+G)=RGb)S (R+G)=RGc)2S=Gd)2G=SCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angleθ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :a)2S (R+G)=RGb)S (R+G)=RGc)2S=Gd)2G=SCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angleθ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :a)2S (R+G)=RGb)S (R+G)=RGc)2S=Gd)2G=SCorrect answer is option 'B'. Can you explain this answer?.
To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angleθ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :a)2S (R+G)=RGb)S (R+G)=RGc)2S=Gd)2G=SCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angleθ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :a)2S (R+G)=RGb)S (R+G)=RGc)2S=Gd)2G=SCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angleθ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :a)2S (R+G)=RGb)S (R+G)=RGc)2S=Gd)2G=SCorrect answer is option 'B'. Can you explain this answer?.
Solutions for To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angleθ. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :a)2S (R+G)=RGb)S (R+G)=RGc)2S=Gd)2G=SCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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