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The isotope having a mass 12.014 u undergoes β-decay to . has an excited state of the nucleusat4.041 MeV above its ground state. If decays to , the maximum kinetic energy of the β- particle in units of MeV is(1 u = 931.5 MeV/c2, where c is the speed of light in vacuum).Correct answer is '9'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The isotope having a mass 12.014 u undergoes β-decay to . has an excited state of the nucleusat4.041 MeV above its ground state. If decays to , the maximum kinetic energy of the β- particle in units of MeV is(1 u = 931.5 MeV/c2, where c is the speed of light in vacuum).Correct answer is '9'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The isotope having a mass 12.014 u undergoes β-decay to . has an excited state of the nucleusat4.041 MeV above its ground state. If decays to , the maximum kinetic energy of the β- particle in units of MeV is(1 u = 931.5 MeV/c2, where c is the speed of light in vacuum).Correct answer is '9'. Can you explain this answer?.

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