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Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer?.
Solutions for Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Inst. Q No. 37 - 41 carry 3 marks eachEach question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.Q.Let Suppose α1 and β1 are the roots of the equation x2 – 2x secθ + 1 = 0 and α2 and β2 arethe roots of the equation x2 + 2x tanθ – 1 = 0. If α1 > β1 and α2 > β2, then α1 + β2 equalsa)2(sec θ – tan θ)b)2 secθc)– 2 tanθd)0Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.