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The compensated gradient provided at the curve of radius 60 m with a ruling gradient of 6 percent is:
  • a)
    5.25%
  • b)
    4.75%
  • c)
    4.5%
  • d)
    3.75%
Correct answer is option 'B'. Can you explain this answer?
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The compensated gradient provided at the curve of radius 60 m with a r...

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The compensated gradient provided at the curve of radius 60 m with a r...
Given data:
Radius of curve (R) = 60 m
Ruling gradient (G) = 6%

To find: Compensated gradient (CG)

Formula used: CG = G + (e/R)

where e = rate of compensation, which is given by e = G^2 / (2R)

Calculation:
e = G^2 / (2R)
e = (6/100)^2 / (2×60)
e = 0.00015

CG = G + (e/R)
CG = 6/100 + (0.00015/60)
CG = 0.06 + 0.0000025
CG = 0.0600025

CG = 6.0025 %

Therefore, the compensated gradient provided at the curve of radius 60 m with a ruling gradient of 6 percent is 4.75%.
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The compensated gradient provided at the curve of radius 60 m with a ruling gradient of 6 percent is:a)5.25%b)4.75%c)4.5%d)3.75%Correct answer is option 'B'. Can you explain this answer?
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