JEE Exam > JEE Questions > In a resonance tube experiment, a closed orga...
Start Learning for Free
In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :
- a)minimum length of water column to have the resonance is 45 cm.
- b)the distance between two succesive nodes is 50 cm.
- c)the maximum length of water column to create the resonance is 95 cm.
- d)none of these.
Correct answer is option 'A,B,C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
In a resonance tube experiment, a closed organ pipe of length 120 cm r...
Most Upvoted Answer
In a resonance tube experiment, a closed organ pipe of length 120 cm r...
Resonance Tube Experiment
Resonance tube experiment is used to determine the speed of sound in air. It involves a tuning fork and a closed organ pipe.
Given Data
Length of the organ pipe = 120 cm
Frequency of tuning fork = 340 Hz
Velocity of sound in air = 340 m/s
Solution
a) Minimum length of water column to have the resonance is 45 cm.
In a closed organ pipe, the wavelength of the sound wave is 2L, where L is the length of the pipe. The frequency of the sound wave is given by the formula:
f = v/2L
where v is the velocity of sound in air.
When the tuning fork is struck, it produces sound waves of frequency 340 Hz. If the length of the pipe is such that it resonates with the frequency of the tuning fork, then the wavelength of the sound wave is equal to twice the length of the pipe. i.e.
2L = v/f
= 340/340
= 1 m
L = 0.5 m = 50 cm
Therefore, the minimum length of water column required to have resonance is:
Minimum length of water column = Length of pipe - Length of air column
= 120 - 50
= 70 cm
But, since water is poured in the pipe, the effective length of the air column is reduced. Let the length of water column be x cm.
Then, the effective length of air column is (120 - x) cm.
For resonance, the effective length of air column should be equal to half the wavelength of the sound wave produced by the tuning fork. i.e.
120 - x = 0.5 m
x = 70 cm - 50 cm
x = 20 cm
Therefore, the minimum length of water column required to have resonance is:
Minimum length of water column = Length of pipe - Length of effective air column
= 120 - 20
= 100 cm
But, the question asks for the minimum length of water column. Therefore, we need to subtract the length of air column at resonance from the length of the pipe.
Minimum length of water column = Length of pipe - Length of air column at resonance
= 120 - 50
= 70 cm
b) The distance between two successive nodes is 50 cm.
In a closed organ pipe, the distance between two successive nodes is equal to half the wavelength of the sound wave produced by the tuning fork. i.e.
Distance between two successive nodes = 0.5 x wavelength
= 0.5 x 2L
= L
= 50 cm
Therefore, the distance between two successive nodes is 50 cm.
c) The maximum length of water column to create the resonance is 95 cm.
For resonance, the effective length of air column should be equal to half the wavelength of the sound wave produced by the tuning fork. i.e.
120 - x = 0.5 m
x = 70 cm
Therefore, the length of air column at resonance is:
Length of air column at resonance = Length of pipe - Length of water column
= 120 - 70
= 50 cm
But, the question asks for the maximum length of water column. Therefore, we need to subtract the length of air column at minimum resonance from the length of the pipe.
Maximum length of water column =
Resonance tube experiment is used to determine the speed of sound in air. It involves a tuning fork and a closed organ pipe.
Given Data
Length of the organ pipe = 120 cm
Frequency of tuning fork = 340 Hz
Velocity of sound in air = 340 m/s
Solution
a) Minimum length of water column to have the resonance is 45 cm.
In a closed organ pipe, the wavelength of the sound wave is 2L, where L is the length of the pipe. The frequency of the sound wave is given by the formula:
f = v/2L
where v is the velocity of sound in air.
When the tuning fork is struck, it produces sound waves of frequency 340 Hz. If the length of the pipe is such that it resonates with the frequency of the tuning fork, then the wavelength of the sound wave is equal to twice the length of the pipe. i.e.
2L = v/f
= 340/340
= 1 m
L = 0.5 m = 50 cm
Therefore, the minimum length of water column required to have resonance is:
Minimum length of water column = Length of pipe - Length of air column
= 120 - 50
= 70 cm
But, since water is poured in the pipe, the effective length of the air column is reduced. Let the length of water column be x cm.
Then, the effective length of air column is (120 - x) cm.
For resonance, the effective length of air column should be equal to half the wavelength of the sound wave produced by the tuning fork. i.e.
120 - x = 0.5 m
x = 70 cm - 50 cm
x = 20 cm
Therefore, the minimum length of water column required to have resonance is:
Minimum length of water column = Length of pipe - Length of effective air column
= 120 - 20
= 100 cm
But, the question asks for the minimum length of water column. Therefore, we need to subtract the length of air column at resonance from the length of the pipe.
Minimum length of water column = Length of pipe - Length of air column at resonance
= 120 - 50
= 70 cm
b) The distance between two successive nodes is 50 cm.
In a closed organ pipe, the distance between two successive nodes is equal to half the wavelength of the sound wave produced by the tuning fork. i.e.
Distance between two successive nodes = 0.5 x wavelength
= 0.5 x 2L
= L
= 50 cm
Therefore, the distance between two successive nodes is 50 cm.
c) The maximum length of water column to create the resonance is 95 cm.
For resonance, the effective length of air column should be equal to half the wavelength of the sound wave produced by the tuning fork. i.e.
120 - x = 0.5 m
x = 70 cm
Therefore, the length of air column at resonance is:
Length of air column at resonance = Length of pipe - Length of water column
= 120 - 70
= 50 cm
But, the question asks for the maximum length of water column. Therefore, we need to subtract the length of air column at minimum resonance from the length of the pipe.
Maximum length of water column =
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer?
Question Description
In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer?.
In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer?.
Solutions for In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer?, a detailed solution for In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? has been provided alongside types of In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe then (given vair = 340 m/sec.) :a)minimum length of water column to have the resonance is 45 cm.b)the distance between two succesive nodes is 50 cm.c)the maximum length of water column to create the resonance is 95 cm.d)none of these.Correct answer is option 'A,B,C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup