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If P(x1, y1), Q(x2, y2) be any two points on the curve y = 3x – 2 – x2 for 1 < x < 2, then maximum value of 3x1 + 3x2 – x12 – x22 is
- a)9
- b)4
- c)2
- d)9/2
Correct answer is option 'D'. Can you explain this answer?
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If P(x1, y1), Q(x2, y2) be any two points on the curve y = 3x – ...
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If P(x1, y1), Q(x2, y2) be any two points on the curve y = 3x – ...
The equation of the curve is given as y = 3x.
Let's consider two points P(x1, y1) and Q(x2, y2) on the curve.
The y-coordinate of point P is given by y1 = 3x1.
The y-coordinate of point Q is given by y2 = 3x2.
So, any two points on the curve can be expressed as P(x1, 3x1) and Q(x2, 3x2), where x1 and x2 are any real numbers.
Let's consider two points P(x1, y1) and Q(x2, y2) on the curve.
The y-coordinate of point P is given by y1 = 3x1.
The y-coordinate of point Q is given by y2 = 3x2.
So, any two points on the curve can be expressed as P(x1, 3x1) and Q(x2, 3x2), where x1 and x2 are any real numbers.
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If P(x1, y1), Q(x2, y2) be any two points on the curve y = 3x – 2 – x2 for 1 < x < 2, then maximum value of3x1 + 3x2 – x12 – x22 isa)9b)4c)2d)9/2Correct answer is option 'D'. Can you explain this answer?
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If P(x1, y1), Q(x2, y2) be any two points on the curve y = 3x – 2 – x2 for 1 < x < 2, then maximum value of3x1 + 3x2 – x12 – x22 isa)9b)4c)2d)9/2Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If P(x1, y1), Q(x2, y2) be any two points on the curve y = 3x – 2 – x2 for 1 < x < 2, then maximum value of3x1 + 3x2 – x12 – x22 isa)9b)4c)2d)9/2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If P(x1, y1), Q(x2, y2) be any two points on the curve y = 3x – 2 – x2 for 1 < x < 2, then maximum value of3x1 + 3x2 – x12 – x22 isa)9b)4c)2d)9/2Correct answer is option 'D'. Can you explain this answer?.
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