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A body dropped from a tower with zero velocity, reaches the ground in 4 seconds. The height of the tower is about
  • a)
    80 m
  • b)
    20 m
  • c)
    160 m
  • d)
    40 m
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A body dropped from a tower with zero velocity, reaches the ground in ...
Put V=u-gt, put u=0 and find v=-4g, now use v^2=u^2+2gh, u=0, then put the value of v and find the value of h it will come 80m
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Community Answer
A body dropped from a tower with zero velocity, reaches the ground in ...
Given data:
- Initial velocity (u) = 0 m/s
- Time taken to reach the ground (t) = 4 seconds
- Acceleration due to gravity (g) = 9.8 m/s²

Using the equation of motion:
- The equation of motion for an object under free fall is:
\[ s = ut + \frac{1}{2}gt^2 \]
where s is the distance fallen, u is the initial velocity, t is the time taken, and g is the acceleration due to gravity.

Calculation:
- Given u = 0, t = 4 seconds, and g = 9.8 m/s²
- Substituting these values in the equation of motion, we get:
\[ s = 0 + \frac{1}{2} \times 9.8 \times (4)^2 \]
\[ s = 0 + \frac{1}{2} \times 9.8 \times 16 \]
\[ s = 0 + 4.9 \times 16 \]
\[ s = 78.4 \text{ meters} \]

Conclusion:
- The height of the tower is approximately 80 meters.
- Therefore, the correct answer is option 'A' - 80 m.
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A body dropped from a tower with zero velocity, reaches the ground in 4 seconds. The height of the tower is abouta)80 mb)20 mc)160 md)40 mCorrect answer is option 'A'. Can you explain this answer?
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