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Three forces i+2j-3k, 2i+3j+4k and i-j+k are acting at a point (0,1,2). The modulus of moment of forces about the point (1,-2,0) is
  • a)
    6√10
  • b)
    4√17
  • c)
    5√10
  • d)
    3√17
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Three forces i+2j-3k, 2i+3j+4k and i-j+k are acting at a point (0,1,2)...
To find the moment of a force about a point, we can use the cross product of the position vector from the point to the force and the force vector itself. The modulus of the moment is then the magnitude of this cross product.

Let's calculate the moment of each force about the point (1,-2,0):

1) Moment of the force 2j - 3k about (1,-2,0):
Position vector from (1,-2,0) to (0,1,2): (0-1, 1-(-2), 2-0) = (-1, 3, 2)
Cross product: (-1) * (-3) - 2 * 2 = -3 + 4 = 1

2) Moment of the force 2i + 3j + 4k about (1,-2,0):
Position vector from (1,-2,0) to (0,1,2): (0-1, 1-(-2), 2-0) = (-1, 3, 2)
Cross product: (-1) * 3 - 2 * 2 = -3 - 4 = -7

3) Moment of the force i - j + k about (1,-2,0):
Position vector from (1,-2,0) to (0,1,2): (0-1, 1-(-2), 2-0) = (-1, 3, 2)
Cross product: (-1) * 3 - 2 * 2 = -3 - 4 = -7

Now, let's calculate the magnitude of the moments:

|1| = 1
|-7| = 7
|-7| = 7

The modulus of the moment of forces about the point (1,-2,0) is 1 + 7 + 7 = 15.
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Three forces i+2j-3k, 2i+3j+4k and i-j+k are acting at a point (0,1,2). The modulus of moment of forces about the point (1,-2,0) isa)6√10b)4√17c)5√10d)3√17Correct answer is option 'A'. Can you explain this answer?
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