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A simply supported beam of rectangular section and span L is subjected to a concentrated load at the mid span. The length of the plastic hinge is–
- a)L/5
- b)L/7
- c)L/4
- d)L/3
Correct answer is option 'D'. Can you explain this answer?
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A simply supported beam of rectangular section and span L is subjected...
The length of the plastic hinge depends on the material properties of the beam and the magnitude of the load. In general, the plastic hinge forms at the location where the bending moment is maximum and exceeds the yield moment of the material.
For a rectangular section beam, the yield moment can be calculated as:
My = (bh^2)/6
where M is the yield moment, b is the width of the beam, and h is the height of the beam.
The maximum bending moment occurs at the midspan and can be calculated as:
Mmax = P*L/4
where P is the magnitude of the concentrated load and L is the span of the beam.
If the bending moment at midspan exceeds the yield moment of the material, a plastic hinge will form. The length of the plastic hinge can be approximated as:
Lp = h*(Mmax/My - 1)
where Lp is the length of the plastic hinge.
Therefore, the length of the plastic hinge for a simply supported beam of rectangular section and span L subjected to a concentrated load at midspan can be calculated using the above equation.
For a rectangular section beam, the yield moment can be calculated as:
My = (bh^2)/6
where M is the yield moment, b is the width of the beam, and h is the height of the beam.
The maximum bending moment occurs at the midspan and can be calculated as:
Mmax = P*L/4
where P is the magnitude of the concentrated load and L is the span of the beam.
If the bending moment at midspan exceeds the yield moment of the material, a plastic hinge will form. The length of the plastic hinge can be approximated as:
Lp = h*(Mmax/My - 1)
where Lp is the length of the plastic hinge.
Therefore, the length of the plastic hinge for a simply supported beam of rectangular section and span L subjected to a concentrated load at midspan can be calculated using the above equation.
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A simply supported beam of rectangular section and span L is subjected...
For point load = L (1-1/shape factor)
for rectangular beam S.F =1.5
= L ( 1-1/1.5)
=L/3
for rectangular beam S.F =1.5
= L ( 1-1/1.5)
=L/3
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A simply supported beam of rectangular section and span L is subjected to a concentrated load at the mid span. The length of the plastic hinge is–a)L/5b)L/7c)L/4d)L/3Correct answer is option 'D'. Can you explain this answer?
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