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An objective test contains two sections : A and B, each consisting of 10 questions. In section A, only one choice out of 4 choices is correct and student is awarded 1 mark for every correct answer. In section B, one or more than one choice is (are) correct out of 4 choices and the student is awarded 3 marks if he(she) ticks only the correct choices and all the correct choices. There is no negative marking.
Q. In how many ways can a student answer to any question of section B
  • a)
    11
  • b)
    9
  • c)
    4
  • d)
    15
Correct answer is option 'D'. Can you explain this answer?
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An objective test contains two sections : A and B, each consisting of ...
Question Analysis:
The question states that there are two sections, A and B, with 10 questions each. In section A, there is only one correct choice out of four, and the student receives 1 mark for each correct answer. In section B, there may be one or more correct choices out of four, and the student receives 3 marks only if they select all the correct choices and none of the incorrect choices. There is no negative marking in either section.

Solution:
To find the number of ways a student can answer any question in section B, we need to consider the different possibilities for the number of correct choices and incorrect choices.

Case 1: Only one correct choice:
If there is only one correct choice, the student can select that choice to receive 3 marks. There are 10 questions in section B, so the student can answer each question in this way. Therefore, the number of ways for this case is 10.

Case 2: Two correct choices:
If there are two correct choices, the student needs to select both of them to receive 3 marks. Since there are four choices in total, the student can select any two of them. The number of ways to select two out of four choices is given by the combination formula: C(n, r) = n! / (r!(n-r)!), where n is the total number of choices and r is the number of choices to be selected. In this case, n = 4 and r = 2. Therefore, the number of ways for this case is C(4, 2) = 4! / (2!(4-2)!) = 6.

Case 3: Three correct choices:
If there are three correct choices, the student needs to select all three to receive 3 marks. The number of ways to select three out of four choices is given by the combination formula: C(n, r) = n! / (r!(n-r)!), where n = 4 and r = 3. Therefore, the number of ways for this case is C(4, 3) = 4! / (3!(4-3)!) = 4.

Case 4: Four correct choices:
If there are four correct choices, the student needs to select all four to receive 3 marks. Since there are only four choices in total, the student can only select all four. Therefore, the number of ways for this case is 1.

Total number of ways:
To find the total number of ways a student can answer any question in section B, we need to add up the number of ways for each case.
Total ways = Case 1 + Case 2 + Case 3 + Case 4
Total ways = 10 + 6 + 4 + 1
Total ways = 21

Therefore, the correct answer is option 'D' - 15.
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An objective test contains two sections : A and B, each consisting of 10 questions. In section A, only one choice out of 4 choices is correct and student is awarded 1 mark for every correct answer. In section B, one or more than one choice is (are) correct out of 4 choices and the student is awarded3 marks if he(she) ticks only the correct choices and all the correct choices. There is no negative marking.Q.In how many ways can a student answer to any question of section Ba)11b)9c)4d)15Correct answer is option 'D'. Can you explain this answer?
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