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SECTION-IV (Integer Type)
This section contains TEN questions. The answer to each question is a single digit integer ranging from 0 to 9.
Enter only the numerical value in the space provided below.
Q. A student performs a titration with different burettes and finds titre values of 25.2 mL, 25.25 mL and 25.0
mL. The number of significant figures in the average titre value is
    Correct answer is '3'. Can you explain this answer?
    Most Upvoted Answer
    SECTION-IV (Integer Type)This section contains TEN questions. The answ...
    Average titre=25.2+25.25+25.0÷3
    =75.45÷3
    =25.15
    =25.2 mL
    Therefore total no. of significant figure is 3 .
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    SECTION-IV (Integer Type)This section contains TEN questions. The answ...
    Explanation:
    When performing measurements in a laboratory setting, it is important to consider the number of significant figures in the final result. The number of significant figures indicates the precision of the measurement and provides information about the certainty of the value obtained.

    In this case, the student performed a titration and obtained three different titre values: 25.2 mL, 25.25 mL, and 25.0 mL. To determine the average titre value, we need to consider the number of significant figures in each measurement.

    The general rule for determining the number of significant figures is as follows:

    1. Non-zero digits are always significant.
    2. Zeros between non-zero digits are also significant.
    3. Leading zeros (zeros before non-zero digits) are not significant.
    4. Trailing zeros (zeros after non-zero digits and after the decimal point) are significant.

    Now, let's analyze the significant figures in each measurement:

    1. 25.2 mL:
    - The digit '2' is non-zero and significant.
    - The digit '5' is non-zero and significant.
    - The digit '2' is non-zero and significant.
    - There are three significant figures in this measurement.

    2. 25.25 mL:
    - The digit '2' is non-zero and significant.
    - The digit '5' is non-zero and significant.
    - The digit '2' is non-zero and significant.
    - The digit '5' is non-zero and significant.
    - There are four significant figures in this measurement.

    3. 25.0 mL:
    - The digit '2' is non-zero and significant.
    - The digit '5' is non-zero and significant.
    - The digit '0' is a trailing zero and significant.
    - There are three significant figures in this measurement.

    To calculate the average titre value, we add the three measurements and divide by the number of measurements (3):

    (25.2 mL + 25.25 mL + 25.0 mL) / 3 = 75.45 mL / 3 = 25.15 mL

    Since the measurement with the fewest significant figures (three) is 25.0 mL, we need to round the average titre value to three significant figures. Therefore, the average titre value is 25.2 mL.

    Hence, the correct answer is '3' significant figures.
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    SECTION-IV (Integer Type)This section contains TEN questions. The answer to each question is a single digit integer ranging from 0 to 9.Enter only the numerical value in the space provided below.Q. A student performs a titration with different burettes and finds titre values of 25.2 mL, 25.25 mL and 25.0mL. The number of significant figures in the average titre value isCorrect answer is '3'. Can you explain this answer?
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