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The HCF of two number is 12 and their LCM is 144. If one of them is 36, then find the other.
  • a)
    24
  • b)
    36
  • c)
    42
  • d)
    48
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The HCF of two number is 12 and their LCM is 144. If one of them is 36...
GIVEN:
HCF of two numbers = 12
LCM of two numbers = 144
One number = 36
FORMULA USED:
Product of two number = LCM × HCF
CALCULATION:
let other number be y
36 × y = 12 × 144
∴ y = 48
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Most Upvoted Answer
The HCF of two number is 12 and their LCM is 144. If one of them is 36...
Problem Statement:

The HCF of two number is 12 and their LCM is 144. If one of them is 36, then find the other.

Solution:

Given that, HCF of two numbers = 12
LCM of two numbers = 144
One number = 36

Let's assume the other number as 'x'.

LCM * HCF = Product of Two Numbers
144 * 12 = 36 * x

1728 = 36x

x = 1728/36
x = 48

Therefore, the other number is 48.

Answer: Option D (48)
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Community Answer
The HCF of two number is 12 and their LCM is 144. If one of them is 36...
Let two numbers be x

another number be y

HCF=12, LCM=144

let x=36,

LCM/HCF=144/12=12

LCM=12HCF


let option-D y=48, x=36

LCM of x, y is |48, 36|

3|16, 12|

3*2|8, 6|

6*2|4, 3|

12*4*3=144

LCM=12HCF

144=12HCF

HCF=12.

Hence, option-D satisfied both the given conditions LCM, HCF
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The HCF of two number is 12 and their LCM is 144. If one of them is 36, then find the other.a)24b)36c)42d)48Correct answer is option 'D'. Can you explain this answer?
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