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A centrifugal pump running at 500 rpm and at its maximum efficiency is delivering a head of 30 m at a flow rate of 60 liters per minute. If the rpm is changed to 1000, then the head H in metres and flow rate Q in litres per minute at maximum efficiency are estimated to be
  • a)
    H = 60, Q = 120
  • b)
    H = 120, Q = 120
  • c)
    H = 60, Q = 480
  • d)
    H= 120, Q = 30
Correct answer is option 'B'. Can you explain this answer?
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A centrifugal pump running at 500 rpm and at its maximum efficiency is...

We also know that specific speed will be constant.
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A centrifugal pump running at 500 rpm and at its maximum efficiency is...
Given information:
- Centrifugal pump speed (N1) = 500 rpm
- Maximum efficiency at N1
- Head (H1) = 30 m
- Flow rate (Q1) = 60 L/min

Required information:
- Head (H2) and flow rate (Q2) at maximum efficiency when speed (N2) = 1000 rpm

Assumptions:
- The pump operates within its design limits and the performance is not affected by other factors such as cavitation.

Explanation:
1. Relationship between head, speed, and flow rate:
- The head, flow rate, and speed of a centrifugal pump are related by the affinity laws.
- According to the affinity laws, the head is proportional to the square of the speed, while the flow rate is directly proportional to the speed.

2. Affinity laws:
The affinity laws for centrifugal pumps are given by the following equations:
- Head ratio (H2/H1) = (N2/N1)^2
- Flow rate ratio (Q2/Q1) = N2/N1

3. Calculating head at N2:
Using the affinity law equation for the head ratio:
- (H2/30) = (1000/500)^2
- H2 = 30 * (1000/500)^2
- H2 = 30 * 4
- H2 = 120 m

4. Calculating flow rate at N2:
Using the affinity law equation for the flow rate ratio:
- (Q2/60) = 1000/500
- Q2 = 60 * (1000/500)
- Q2 = 60 * 2
- Q2 = 120 L/min

Conclusion:
At maximum efficiency, when the speed is changed from 500 rpm to 1000 rpm, the estimated values for head (H2) and flow rate (Q2) are:
- H2 = 120 m
- Q2 = 120 L/min

Therefore, the correct answer is option 'B' (H = 120, Q = 120).
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A centrifugal pump running at 500 rpm and at its maximum efficiency is delivering a head of 30 m at a flow rate of 60 liters per minute. If the rpm is changed to 1000, then the head H in metres and flow rate Q in litres per minute at maximum efficiency are estimated to bea)H = 60, Q = 120b)H = 120, Q = 120c)H = 60, Q = 480d)H= 120, Q = 30Correct answer is option 'B'. Can you explain this answer?
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