JEE Exam > JEE Questions > In a reversible reaction, two substances are ...
Start Learning for Free
In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will be
- a)reduced to half of its original value
- b)doubled
- c)same
- d)reduced to one fourth its original value
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
In a reversible reaction, two substances are in equilibrium. If the co...
Actually, here remember the value of eqm constants,Kp and Kc is always constant and changes only with temperature.
Free Test
FREE
| Start Free Test |
Community Answer
In a reversible reaction, two substances are in equilibrium. If the co...
Explanation:
When a reversible reaction is at equilibrium, the concentrations of the reactants and products remain constant. The equilibrium constant (K) is a numerical value that represents the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium.
In this case, let's consider a reversible reaction represented as:
A + B ⇌ C + D
Where A and B are reactants and C and D are products.
Now, if the concentration of each substance is reduced to half, we can denote the new concentrations as:
[A] = [A]₀/2
[B] = [B]₀/2
[C] = [C]₀/2
[D] = [D]₀/2
The equilibrium constant (K) is defined as:
K = ([C] * [D]) / ([A] * [B])
Substituting the new concentrations into the equilibrium constant expression, we get:
K' = ([C]₀/2 * [D]₀/2) / ([A]₀/2 * [B]₀/2)
Simplifying the expression, we have:
K' = ([C]₀ * [D]₀) / ([A]₀ * [B]₀) * (1/2 * 1/2)
K' = K * (1/4)
Therefore, the equilibrium constant (K') is reduced to one-fourth (1/4) of its original value (K). Hence, the correct answer is option 'D', i.e., "reduced to one-fourth its original value".
It's important to note that the equilibrium constant depends only on the stoichiometry of the reaction and the temperature, but not on the initial concentrations of the reactants and products. Therefore, reducing the concentration of each substance to half does not change the equilibrium constant value.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer?
Question Description
In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer?.
In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer?.
Solutions for In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a reversible reaction, two substances are in equilibrium. If the concentration of each one is reduced to half, the equilibrium constant will bea)reduced to half of its original valueb)doubledc)samed)reduced to one fourth its original valueCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup