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Sumit constructs a wall working in a special way and takes 12 days to complete it. If Sn is the length of the wall (in m) that he constructs on the nth day, then
Sn = 2n, 0 ≤ n ≤ 4
Sn = 8, for n = 5
Sn = 3n - 7, 6 ≤ n ≤ 12
Find the total length of the wall he constructs in the first 10 days.
  • a)
    131m
  • b)
    115m
  • c)
    113m
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Sumit constructs a wall working in a special way and takes 12 days to ...
Let us make a table of the units of work everyday :

    ► Total length =113 m
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Most Upvoted Answer
Sumit constructs a wall working in a special way and takes 12 days to ...
Since Sn represents the length of the wall that Sumit constructs on the nth day, and the wall is constructed in a special way, we can observe that the length of the wall doubles every day.

So, on the first day (n=1), the length of the wall is 2*1=2m.
On the second day (n=2), the length of the wall is 2*2=4m.
On the third day (n=3), the length of the wall is 2*3=6m.

Similarly, we can continue this pattern to find the length of the wall on the 12th day.

On the 12th day (n=12), the length of the wall is 2*12=24m.

Therefore, Sn = 2n represents the length of the wall (in m) that Sumit constructs on the nth day, and Sn = 24 when n = 12.
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Sumit constructs a wall working in a special way and takes 12 days to complete it. If Sn is the length of the wall (in m) that he constructs on the nth day, thenSn = 2n, 0 ≤ n ≤ 4Sn = 8, for n = 5Sn = 3n - 7, 6 ≤ n ≤ 12Find the total length of the wall he constructs in the first 10 days.a)131mb)115mc)113md)None of theseCorrect answer is option 'C'. Can you explain this answer?
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