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One type of anaerobic respiration converts glucose, C6H12O6, to ethanol C2​H5​OH and carbon dioxide. If the molecular weight of glucose is 180 grams/mol and the molar mass of ethanol is 50 g/mol how many grams of carbon dioxide are produced when 1 mol of glucose is digested via respiration?

  • a)
    88 grams

  • b)
    0 grams

  • c)
    40 grams

  • d)
    None of these

Correct answer is option 'A'. Can you explain this answer?
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One type of anaerobic respiration converts glucose,C6H12O6, to ethanol...
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One type of anaerobic respiration converts glucose,C6H12O6, to ethanol...
Calculation:

The balanced chemical equation for the anaerobic respiration of glucose to ethanol and carbon dioxide is as follows:

C6H12O6 → 2C2H5OH + 2CO2

From the equation, we can see that 1 mole of glucose produces 2 moles of carbon dioxide.

Molar mass of glucose = 180 g/mol

Number of moles of glucose = 1 mol

Therefore, the mass of glucose = molar mass × number of moles

= 180 g/mol × 1 mol

= 180 g

Number of moles of carbon dioxide produced = 2 moles

Molar mass of carbon dioxide = 44 g/mol

Therefore, the mass of carbon dioxide produced = molar mass × number of moles

= 44 g/mol × 2 moles

= 88 g

Hence, the answer is option A, 88 grams.
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One type of anaerobic respiration converts glucose,C6H12O6, to ethanol C2H5OHand carbon dioxide. If the molecular weight of glucose is180 grams/mol and the molar mass of ethanol is50 g/mol how many grams of carbon dioxide are produced when1mol of glucose is digested via respiration?a)88gramsb)0 gramsc)40 gramsd)None of theseCorrect answer is option 'A'. Can you explain this answer?
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