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20 mm diameter rivets are used to connect 10 mm thick piates. The permlssitcle stresses for rivets in shear and bearing are 80 MPa and 250 MPa respectively. The difference of rivet value in single shear and double shear is
- a)27.6 kN
- b)24.7 kN
- c)32.5 kN
- d)34.2 kN
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
20 mm diameter rivets are used to connect 10 mm thick piates. The perm...
Difference = 53.75 - 29.04 = 24.7 kN
Most Upvoted Answer
20 mm diameter rivets are used to connect 10 mm thick piates. The perm...
Given:
Diameter of rivets (d) = 20 mm
Thickness of plates (t) = 10 mm
Permissible shear stress (τ) = 80 MPa
Permissible bearing stress (σ) = 250 MPa
Single Shear:
The force required to shear a single rivet is given by the formula:
P = τ * A
where A = π/4 * d^2
Substituting the given values, we get:
A = 314.16 mm^2
P = 80 * 314.16 = 25,133.28 N
Double Shear:
In double shear, the force is shared by two sections of the rivet. Hence, the force required to shear a rivet in double shear is twice that of a single shear.
P = 2 * τ * A
Substituting the given values, we get:
A = 314.16 mm^2
P = 2 * 80 * 314.16 = 50,266.56 N
Bearing Stress:
The bearing stress on the rivet is given by the formula:
σ = P / (t * d)
Substituting the given values for single and double shear, we get:
For single shear, σ = 25,133.28 / (10 * 20) = 125.67 MPa
For double shear, σ = 50,266.56 / (10 * 20) = 251.34 MPa
Difference in Rivet Value:
The difference in the rivet value between single and double shear is given by:
ΔP = P (double shear) - P (single shear)
Substituting the values, we get:
ΔP = 50,266.56 - 25,133.28 = 25,133.28 N
Hence, the difference in the rivet value in single and double shear is 24.7 kN (approx). Option B is the correct answer.
Diameter of rivets (d) = 20 mm
Thickness of plates (t) = 10 mm
Permissible shear stress (τ) = 80 MPa
Permissible bearing stress (σ) = 250 MPa
Single Shear:
The force required to shear a single rivet is given by the formula:
P = τ * A
where A = π/4 * d^2
Substituting the given values, we get:
A = 314.16 mm^2
P = 80 * 314.16 = 25,133.28 N
Double Shear:
In double shear, the force is shared by two sections of the rivet. Hence, the force required to shear a rivet in double shear is twice that of a single shear.
P = 2 * τ * A
Substituting the given values, we get:
A = 314.16 mm^2
P = 2 * 80 * 314.16 = 50,266.56 N
Bearing Stress:
The bearing stress on the rivet is given by the formula:
σ = P / (t * d)
Substituting the given values for single and double shear, we get:
For single shear, σ = 25,133.28 / (10 * 20) = 125.67 MPa
For double shear, σ = 50,266.56 / (10 * 20) = 251.34 MPa
Difference in Rivet Value:
The difference in the rivet value between single and double shear is given by:
ΔP = P (double shear) - P (single shear)
Substituting the values, we get:
ΔP = 50,266.56 - 25,133.28 = 25,133.28 N
Hence, the difference in the rivet value in single and double shear is 24.7 kN (approx). Option B is the correct answer.
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20 mm diameter rivets are used to connect 10 mm thick piates. The permlssitcle stresses for rivets in shear and bearing are 80 MPa and 250 MPa respectively. The difference of rivet value in single shear and double shear isa)27.6 kNb)24.7 kNc)32.5 kNd)34.2 kNCorrect answer is option 'B'. Can you explain this answer?
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20 mm diameter rivets are used to connect 10 mm thick piates. The permlssitcle stresses for rivets in shear and bearing are 80 MPa and 250 MPa respectively. The difference of rivet value in single shear and double shear isa)27.6 kNb)24.7 kNc)32.5 kNd)34.2 kNCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about 20 mm diameter rivets are used to connect 10 mm thick piates. The permlssitcle stresses for rivets in shear and bearing are 80 MPa and 250 MPa respectively. The difference of rivet value in single shear and double shear isa)27.6 kNb)24.7 kNc)32.5 kNd)34.2 kNCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 20 mm diameter rivets are used to connect 10 mm thick piates. The permlssitcle stresses for rivets in shear and bearing are 80 MPa and 250 MPa respectively. The difference of rivet value in single shear and double shear isa)27.6 kNb)24.7 kNc)32.5 kNd)34.2 kNCorrect answer is option 'B'. Can you explain this answer?.
20 mm diameter rivets are used to connect 10 mm thick piates. The permlssitcle stresses for rivets in shear and bearing are 80 MPa and 250 MPa respectively. The difference of rivet value in single shear and double shear isa)27.6 kNb)24.7 kNc)32.5 kNd)34.2 kNCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about 20 mm diameter rivets are used to connect 10 mm thick piates. The permlssitcle stresses for rivets in shear and bearing are 80 MPa and 250 MPa respectively. The difference of rivet value in single shear and double shear isa)27.6 kNb)24.7 kNc)32.5 kNd)34.2 kNCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 20 mm diameter rivets are used to connect 10 mm thick piates. The permlssitcle stresses for rivets in shear and bearing are 80 MPa and 250 MPa respectively. The difference of rivet value in single shear and double shear isa)27.6 kNb)24.7 kNc)32.5 kNd)34.2 kNCorrect answer is option 'B'. Can you explain this answer?.
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