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A current of 3 A flows through a resistor of 20 ohms. The energy dissipated in the resistor per minute is
  • a)
    0.18 W    
  • b)
    1.8 W
  • c)
    180 W    
  • d)
    3.6 W
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A current of 3 A flows through a resistor of 20 ohms. The energy dissi...
Power dissipated by the resistor is
P = I2 R = 32 x 20 = 180 W
Now, energy dissipated by the resistor in one hour (or 60 min)
= [180 x 60] watt-min
∴ Energy dissipated by the resistor in one minutes
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Most Upvoted Answer
A current of 3 A flows through a resistor of 20 ohms. The energy dissi...
Given data:
Current flowing through the resistor, I = 3 A
Resistance of the resistor, R = 20 Ω

To find:
Energy dissipated in the resistor per minute

Formula:
The power dissipated in a resistor can be calculated using the formula: P = I^2 * R

Calculation:
Given that the current flowing through the resistor is 3 A and the resistance is 20 Ω.

Using the formula, we can calculate the power dissipated in the resistor as follows:
P = I^2 * R
P = (3 A)^2 * 20 Ω
P = 9 A^2 * 20 Ω
P = 180 A^2 * Ω

We know that 1 watt is equal to 1 A^2 * Ω. Therefore, the power dissipated in the resistor is 180 W.

Since the question asks for the energy dissipated in the resistor per minute, we need to convert the power to energy using the equation: Energy = Power * time

Given that the time is 1 minute, we can calculate the energy dissipated as follows:
Energy = Power * time
Energy = 180 W * 1 min
Energy = 180 W-min

Therefore, the energy dissipated in the resistor per minute is 180 W.

Answer:
The correct option is c) 180 W.
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A current of 3 A flows through a resistor of 20 ohms. The energy dissipated in the resistor per minute isa)0.18 W b)1.8 Wc)180 W d)3.6 WCorrect answer is option 'C'. Can you explain this answer?
Question Description
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