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A current of 5A flows in a resistor of 2 ohm. Calculate the power in the resistor and the energy dissipated in 300 seconds.
  • a)
    15kJ
  • b)
    15000kJ
  • c)
    1500J
  • d)
    15J
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A current of 5A flows in a resistor of 2 ohm. Calculate the power in t...
Calculation of Power in the Resistor:

Given, current flowing through the resistor (I) = 5A
Resistance (R) = 2 ohm

Using Ohm's law, V = IR
Voltage (V) = IR = 5A × 2 ohm = 10V

Power (P) = VI = 10V × 5A = 50W

Therefore, the power in the resistor is 50W.

Calculation of Energy Dissipated in 300 Seconds:

Time (t) = 300 seconds

Using the formula, E = Pt, where E is the energy dissipated, P is the power and t is the time.

Substituting the values, E = 50W × 300s = 15000J

Therefore, the energy dissipated in 300 seconds is 15 kJ (kilojoules).

Hence, the correct option is A.
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Community Answer
A current of 5A flows in a resistor of 2 ohm. Calculate the power in t...
P=I^2R =5^2*2=50W.
E= Pt=50*300=15000J=15kJ.
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A current of 5A flows in a resistor of 2 ohm. Calculate the power in the resistor and the energy dissipated in 300 seconds.a)15kJb)15000kJc)1500Jd)15JCorrect answer is option 'A'. Can you explain this answer?
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