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For the circuit of 0.25 ohm and 0.2 ohm. Resistor and volage of 12 and 12 find the current supplied by each battery and power disscipated in1ohm resistor
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For the circuit of 0.25 ohm and 0.2 ohm. Resistor and volage of 12 and...
Node-Voltage Analysis of Resistive Circuit
Node-voltage analysis is a method used to analyze circuits in which the circuit is divided into nodes and the voltages at these nodes are determined. This method is particularly useful for circuits with multiple voltage sources and resistors.
Given Circuit Parameters
- Resistors: 0.25 ohm, 0.2 ohm, and 1 ohm
- Voltage Sources: 12V each
Calculating Current Supplied by Each Battery
- Since the resistors are in series, the total resistance in the circuit is 0.25 + 0.2 + 1 = 1.45 ohms.
- The total current in the circuit can be calculated using Ohm's Law: I = V/R = 12V / 1.45 ohms = 8.28A.
- The current supplied by each battery is the same in a series circuit, so each battery supplies 8.28A.
Power Dissipated in 1 ohm Resistor
- The power dissipated in a resistor can be calculated using the formula P = I^2 * R, where I is the current and R is the resistance.
- For the 1 ohm resistor, the current is 8.28A and the resistance is 1 ohm.
- Therefore, the power dissipated in the 1 ohm resistor is P = (8.28A)^2 * 1 ohm = 69.03W.
In this circuit, the current supplied by each battery is 8.28A, and the power dissipated in the 1 ohm resistor is 69.03W. This analysis helps in understanding the behavior of the circuit and how the components interact with each other to determine the flow of current and power dissipation.
Node-voltage analysis is a method used to analyze circuits in which the circuit is divided into nodes and the voltages at these nodes are determined. This method is particularly useful for circuits with multiple voltage sources and resistors.
Given Circuit Parameters
- Resistors: 0.25 ohm, 0.2 ohm, and 1 ohm
- Voltage Sources: 12V each
Calculating Current Supplied by Each Battery
- Since the resistors are in series, the total resistance in the circuit is 0.25 + 0.2 + 1 = 1.45 ohms.
- The total current in the circuit can be calculated using Ohm's Law: I = V/R = 12V / 1.45 ohms = 8.28A.
- The current supplied by each battery is the same in a series circuit, so each battery supplies 8.28A.
Power Dissipated in 1 ohm Resistor
- The power dissipated in a resistor can be calculated using the formula P = I^2 * R, where I is the current and R is the resistance.
- For the 1 ohm resistor, the current is 8.28A and the resistance is 1 ohm.
- Therefore, the power dissipated in the 1 ohm resistor is P = (8.28A)^2 * 1 ohm = 69.03W.
In this circuit, the current supplied by each battery is 8.28A, and the power dissipated in the 1 ohm resistor is 69.03W. This analysis helps in understanding the behavior of the circuit and how the components interact with each other to determine the flow of current and power dissipation.
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For the circuit of 0.25 ohm and 0.2 ohm. Resistor and volage of 12 and 12 find the current supplied by each battery and power disscipated in1ohm resistor Related: Node-voltage analysis of resistive circuit in the context of dc voltages and currents
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