two metallic oxides contain 27.6 percent and 30% oxygen respectively i...
Given that, formula of first oxide = M3O4Let mass of the metal = x% of metal in M3O4 = (3x/ 3x+64) *100but as given % age = (100-27.6) = 72.4 %so, (3x/3x+64)*100 = 72.4or x = 56.in 2nd oxide,oxygen = 30%....so metal = 70%so, the ratio isM : O70/56 : 30/161.25 : 1.8752 : 3so, 2nd oxide is M2O3.
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two metallic oxides contain 27.6 percent and 30% oxygen respectively i...
Explanation:
Given:
- First oxide contains 27.6% oxygen.
- Second oxide contains 30% oxygen.
- Formula of the first oxide is M3O4.
Calculating the ratio of metal to oxygen:
- For the first oxide, the ratio of oxygen to metal can be calculated as follows:
- Oxygen: 27.6%
- Metal: 100% - 27.6% = 72.4%
- Ratio of metal to oxygen = 72.4%/27.6% = 2.62:1
- For the second oxide, the ratio of oxygen to metal can be calculated as follows:
- Oxygen: 30%
- Metal: 100% - 30% = 70%
- Ratio of metal to oxygen = 70%/30% = 2.33:1
Determining the formula of the second oxide:
- Since the ratio of metal to oxygen in the first oxide is 2.62:1, the formula can be represented as M3O4.
- To find the formula for the second oxide with a metal to oxygen ratio of 2.33:1, we look for the simplest whole number ratio.
- Dividing the ratio 2.62:1 by the greatest common divisor (GCD) gives us the simplest ratio: 2.62 ÷ 1.31 = 2:1.
- Therefore, the formula for the second oxide with a metal to oxygen ratio of 2:1 is MO2.
Conclusion:
- The formula of the second metallic oxide is MO2.
two metallic oxides contain 27.6 percent and 30% oxygen respectively i...
c m2o5
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