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A hypothetical element (Y) has two oxides A and B . YO contains 40% oxygen and the second oxide contains 20% oxygen then find the formula of second oxide?
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A hypothetical element (Y) has two oxides A and B . YO contains 40% ox...
Formula of Second Oxide of Hypothetical Element Y


Given Information


  • Element Y has two oxides A and B

  • YO contains 40% oxygen

  • The second oxide contains 20% oxygen



Solution

Let's assume the formula of the first oxide A to be YaOx. As it contains 40% oxygen, we can write:

Mass of oxygen = 40g

Mass of Y = 60g

Now, let's assume the formula of the second oxide B to be YbOy. As it contains 20% oxygen, we can write:

Mass of oxygen = 20g

Mass of Y = 80g

Now, we need to find the formula of YbOy. We can do this by finding the ratio of Y and O in both oxides:

Ratio of Y and O in YaOx:

Y : O = 60 : 40 = 3 : 2

Ratio of Y and O in YbOy:

Y : O = 80 : 20 = 4 : 1

As we can see, the ratio of Y and O in both oxides is different. To make it equal, we need to multiply the ratio of Y and O in YaOx by 2:

Y : O = 3 x 2 : 2 x 2 = 6 : 4 = 3 : 2

Now, the ratio of Y and O in both oxides is the same. This means the formula of YbOy is:

YbOy = YaOx x 2

Substituting the values of Y and O in the formula, we get:

YbOy = YaOx x 2

4Y : O = 2Y : X

2Y = X

The formula of the second oxide is YbO2.


Conclusion

The formula of the second oxide of hypothetical element Y is YbO2.
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A hypothetical element (Y) has two oxides A and B . YO contains 40% oxygen and the second oxide contains 20% oxygen then find the formula of second oxide?
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