A hypothetical element (Y) has two oxides A and B . YO contains 40% ox...
Formula of Second Oxide of Hypothetical Element Y
Given Information
- Element Y has two oxides A and B
- YO contains 40% oxygen
- The second oxide contains 20% oxygen
Solution
Let's assume the formula of the first oxide A to be YaOx. As it contains 40% oxygen, we can write:
Mass of oxygen = 40g
Mass of Y = 60g
Now, let's assume the formula of the second oxide B to be YbOy. As it contains 20% oxygen, we can write:
Mass of oxygen = 20g
Mass of Y = 80g
Now, we need to find the formula of YbOy. We can do this by finding the ratio of Y and O in both oxides:
Ratio of Y and O in YaOx:
Y : O = 60 : 40 = 3 : 2
Ratio of Y and O in YbOy:
Y : O = 80 : 20 = 4 : 1
As we can see, the ratio of Y and O in both oxides is different. To make it equal, we need to multiply the ratio of Y and O in YaOx by 2:
Y : O = 3 x 2 : 2 x 2 = 6 : 4 = 3 : 2
Now, the ratio of Y and O in both oxides is the same. This means the formula of YbOy is:
YbOy = YaOx x 2
Substituting the values of Y and O in the formula, we get:
YbOy = YaOx x 2
4Y : O = 2Y : X
2Y = X
The formula of the second oxide is YbO2.
Conclusion
The formula of the second oxide of hypothetical element Y is YbO2.