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A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt = 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate is
- a)120 kN
- b)140kN
- c)160 kN
- d)180 kN
Correct answer is option 'D'. Can you explain this answer?
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A double riveted double cover butt joint in plates 20 mm thick is made...
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A double riveted double cover butt joint in plates 20 mm thick is made...
Assuming the material of the plates and rivets is mild steel, the permissible stresses can be taken as:
Shear stress in rivets: 70 MPa
Bearing stress on plates: 140 MPa
Tensile stress in plates: 140 MPa
To check the adequacy of the joint, we can calculate the required number of rivets, the strength of the joint in shear and bearing, and the tensile strength of the plates.
Number of rivets:
The effective area of one rivet is π/4 x d^2 = π/4 x 25^2 = 490.9 mm^2
The effective area of the plates in double shear is 2 x 20 x 100 = 4000 mm^2
The required number of rivets is therefore 4000/490.9 = 8.14, say 9.
Strength of joint in shear:
The strength of one rivet in shear is 70 x 490.9 = 34.36 kN
The total strength of 9 rivets is 9 x 34.36 = 309.24 kN
The maximum shear force that can be resisted by the joint is 0.6 x 140 x 4000 = 336 kN
Therefore, the joint is adequate in shear.
Strength of joint in bearing:
The bearing stress on one plate is 140 x 20 = 2800 N/mm
The bearing strength of one rivet is 2800 x 25 = 70 kN
The total bearing strength of 9 rivets is 9 x 70 = 630 kN
The maximum bearing force that can be resisted by the joint is 0.6 x 140 x 20 x 100 = 1680 kN
Therefore, the joint is adequate in bearing.
Tensile strength of plates:
The tensile strength of one plate is 140 x 20 x 100 = 280 kN
The total tensile strength of the plates is 2 x 280 = 560 kN
The maximum tensile force that can be resisted by the joint is 0.6 x 140 x 20 x 100 = 1680 kN
Therefore, the joint is adequate in tension.
In conclusion, the double riveted double cover butt joint with 25 mm diameter rivets at 100 mm pitch is adequate for the given thickness of plates and the permissible stresses.
Shear stress in rivets: 70 MPa
Bearing stress on plates: 140 MPa
Tensile stress in plates: 140 MPa
To check the adequacy of the joint, we can calculate the required number of rivets, the strength of the joint in shear and bearing, and the tensile strength of the plates.
Number of rivets:
The effective area of one rivet is π/4 x d^2 = π/4 x 25^2 = 490.9 mm^2
The effective area of the plates in double shear is 2 x 20 x 100 = 4000 mm^2
The required number of rivets is therefore 4000/490.9 = 8.14, say 9.
Strength of joint in shear:
The strength of one rivet in shear is 70 x 490.9 = 34.36 kN
The total strength of 9 rivets is 9 x 34.36 = 309.24 kN
The maximum shear force that can be resisted by the joint is 0.6 x 140 x 4000 = 336 kN
Therefore, the joint is adequate in shear.
Strength of joint in bearing:
The bearing stress on one plate is 140 x 20 = 2800 N/mm
The bearing strength of one rivet is 2800 x 25 = 70 kN
The total bearing strength of 9 rivets is 9 x 70 = 630 kN
The maximum bearing force that can be resisted by the joint is 0.6 x 140 x 20 x 100 = 1680 kN
Therefore, the joint is adequate in bearing.
Tensile strength of plates:
The tensile strength of one plate is 140 x 20 x 100 = 280 kN
The total tensile strength of the plates is 2 x 280 = 560 kN
The maximum tensile force that can be resisted by the joint is 0.6 x 140 x 20 x 100 = 1680 kN
Therefore, the joint is adequate in tension.
In conclusion, the double riveted double cover butt joint with 25 mm diameter rivets at 100 mm pitch is adequate for the given thickness of plates and the permissible stresses.
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A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer?.
A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer?.
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A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A double riveted double cover butt joint in plates 20 mm thick is made with 25 mm diameter rivets at 100 mm pitch. The permissible stresses are σt= 120 MPa, τ = 100 MPa, σc= 150 MPa. Taking the strength of the rivet in double shear as twice that of single shear, the tearing resistance of the plate isa)120 kN b)140kNc)160 kN d)180 kNCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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