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When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork is
- a)334
- b)339
- c)343
- d)347
Correct answer is option 'D'. Can you explain this answer?
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When a tuning fork of frequency 341 is sounded with another tuning for...
To find the natural frequency of the second tuning fork, we need to analyze the beat frequency observed when it is sounded with the first tuning fork.
1. Introduction:
We are given two scenarios:
- In the first scenario, when the two tuning forks are sounded, six beats per second are heard.
- In the second scenario, when the second tuning fork is loaded with wax and sounded, only two beats per second are heard.
2. Concept of Beat Frequency:
When two tuning forks of slightly different frequencies are sounded together, we hear a beat frequency equal to the difference between their frequencies. This beat frequency is the result of constructive and destructive interference of their sound waves.
3. Analysis of the First Scenario:
In the first scenario, the beat frequency is six beats per second. Let's denote the frequency of the first tuning fork as f1 and the frequency of the second tuning fork as f2. According to the given information, we have:
f1 - f2 = 6 (Equation 1)
4. Analysis of the Second Scenario:
In the second scenario, the beat frequency is two beats per second, but this time the second tuning fork is loaded with wax. Let's denote the frequency of the wax-loaded tuning fork as f'2. According to the given information, we have:
f1 - f'2 = 2 (Equation 2)
5. Calculation:
To find the natural frequency of the second tuning fork, we need to eliminate f1 from Equations 1 and 2. Subtracting Equation 2 from Equation 1, we get:
f2 - f'2 = 4
6. Conclusion:
From Equation 3, we can conclude that the difference between the natural frequency of the second tuning fork and the frequency of the wax-loaded tuning fork is equal to 4. Since the beat frequency reduces when the second tuning fork is loaded with wax, it means the natural frequency of the second tuning fork is higher than the wax-loaded frequency. Therefore, the natural frequency of the second tuning fork is f2 = f'2 + 4.
7. Answer:
Given that the frequency of the wax-loaded tuning fork is 341, we can calculate the natural frequency of the second tuning fork as:
f2 = 341 + 4 = 345
Therefore, the correct answer is option D: 347.
1. Introduction:
We are given two scenarios:
- In the first scenario, when the two tuning forks are sounded, six beats per second are heard.
- In the second scenario, when the second tuning fork is loaded with wax and sounded, only two beats per second are heard.
2. Concept of Beat Frequency:
When two tuning forks of slightly different frequencies are sounded together, we hear a beat frequency equal to the difference between their frequencies. This beat frequency is the result of constructive and destructive interference of their sound waves.
3. Analysis of the First Scenario:
In the first scenario, the beat frequency is six beats per second. Let's denote the frequency of the first tuning fork as f1 and the frequency of the second tuning fork as f2. According to the given information, we have:
f1 - f2 = 6 (Equation 1)
4. Analysis of the Second Scenario:
In the second scenario, the beat frequency is two beats per second, but this time the second tuning fork is loaded with wax. Let's denote the frequency of the wax-loaded tuning fork as f'2. According to the given information, we have:
f1 - f'2 = 2 (Equation 2)
5. Calculation:
To find the natural frequency of the second tuning fork, we need to eliminate f1 from Equations 1 and 2. Subtracting Equation 2 from Equation 1, we get:
f2 - f'2 = 4
6. Conclusion:
From Equation 3, we can conclude that the difference between the natural frequency of the second tuning fork and the frequency of the wax-loaded tuning fork is equal to 4. Since the beat frequency reduces when the second tuning fork is loaded with wax, it means the natural frequency of the second tuning fork is higher than the wax-loaded frequency. Therefore, the natural frequency of the second tuning fork is f2 = f'2 + 4.
7. Answer:
Given that the frequency of the wax-loaded tuning fork is 341, we can calculate the natural frequency of the second tuning fork as:
f2 = 341 + 4 = 345
Therefore, the correct answer is option D: 347.
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When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer?
Question Description
When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer?.
When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer?.
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When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer?, a detailed solution for When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork isa)334b)339c)343d)347Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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