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A d.c. chopper circuit connected to a 100 V d.c. source supplies an inductive load having 40 mH in series with a resistance of 5 Ω A freewheeling diode is placed across the load. The load current varies between the limits of 10 A and 12 A. The time ratio (Ton/Toff) of the chopper is
  • a)
    1.65    
  • b)
    0.98
  • c)
    1.22    
  • d)
    0.75
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A d.c. chopper circuit connected to a 100 V d.c. source supplies an in...
The average value of load current

The maximum value of load current

Now, the average value of the voltage is

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or, 
or,
or, 
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Most Upvoted Answer
A d.c. chopper circuit connected to a 100 V d.c. source supplies an in...
Ω. The chopper frequency is 10 kHz and the duty ratio is 0.6. Determine:

a) The average output voltage
b) The peak-to-peak output voltage ripple
c) The average current through the inductive load
d) The peak current through the inductive load
e) The power delivered to the load
f) The power delivered by the source

Solution:

a) The average output voltage can be found using the duty ratio as:

Vout_avg = Vdc x Duty Ratio
Vout_avg = 100 V x 0.6
Vout_avg = 60 V

b) The peak-to-peak output voltage ripple can be found using the formula:

Vout_ripple = (Vdc x (1 - Duty Ratio)) / f
Vout_ripple = (100 V x (1 - 0.6)) / 10 kHz
Vout_ripple = 4 V

c) The average current through the inductive load can be found using the formula:

Iout_avg = Vout_avg / (R + L x f)
Iout_avg = 60 V / (5 Ω + 40 mH x 10 kHz)
Iout_avg = 1.2 A

d) The peak current through the inductive load can be found using the formula:

Iout_peak = (Vdc x Duty Ratio) / (L x f)
Iout_peak = (100 V x 0.6) / (40 mH x 10 kHz)
Iout_peak = 0.9 A

e) The power delivered to the load can be found using the formula:

Pout = Vout_avg x Iout_avg
Pout = 60 V x 1.2 A
Pout = 72 W

f) The power delivered by the source can be found using the formula:

Pin = Vdc x Iin_avg
Iin_avg = Iout_avg x (1 - Duty Ratio)
Pin = 100 V x 1.2 A / 0.4
Pin = 300 W

Therefore, the power delivered to the load is 72 W, while the power delivered by the source is 300 W. The difference between these two powers is the power loss in the circuit, which is 228 W.
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A d.c. chopper circuit connected to a 100 V d.c. source supplies an inductive load having 40 mH in series with a resistance of 5 Ω A freewheeling diode is placed across the load. The load current varies between the limits of 10 A and 12 A. The time ratio (Ton/Toff) of the chopper isa)1.65 b)0.98c)1.22 d)0.75Correct answer is option 'C'. Can you explain this answer?
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A d.c. chopper circuit connected to a 100 V d.c. source supplies an inductive load having 40 mH in series with a resistance of 5 Ω A freewheeling diode is placed across the load. The load current varies between the limits of 10 A and 12 A. The time ratio (Ton/Toff) of the chopper isa)1.65 b)0.98c)1.22 d)0.75Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A d.c. chopper circuit connected to a 100 V d.c. source supplies an inductive load having 40 mH in series with a resistance of 5 Ω A freewheeling diode is placed across the load. The load current varies between the limits of 10 A and 12 A. The time ratio (Ton/Toff) of the chopper isa)1.65 b)0.98c)1.22 d)0.75Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A d.c. chopper circuit connected to a 100 V d.c. source supplies an inductive load having 40 mH in series with a resistance of 5 Ω A freewheeling diode is placed across the load. The load current varies between the limits of 10 A and 12 A. The time ratio (Ton/Toff) of the chopper isa)1.65 b)0.98c)1.22 d)0.75Correct answer is option 'C'. Can you explain this answer?.
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