The weight of an undried specimen of clay was 34.62 gm .the oven dry w...
Given:
- Weight of undried clay specimen = 34.62 gm
- Oven dry weight of clay specimen = 20.36 gm
- Volume of clay specimen before oven drying = 24.66 cc
- g = 2.68
Calculations:1. Calculate the moisture content:
Moisture content = (Weight of undried specimen - Oven dry weight of specimen) / Oven dry weight of specimen
Moisture content = (34.62 - 20.36) / 20.36 = 0.702
2. Calculate the mass of water:
Mass of water = Moisture content x Oven dry weight of specimen
Mass of water = 0.702 x 20.36 = 14.28 gm
3. Calculate the bulk density:
Bulk density = Oven dry weight of specimen / Volume of specimen
Bulk density = 20.36 / 24.66 = 0.824 gm/cc
4. Calculate the dry density:
Dry density = Bulk density / (1 + Moisture content)
Dry density = 0.824 / (1 + 0.702) = 0.484 gm/cc
5. Calculate the void ratio:
Void ratio = (Bulk density - Dry density) / Dry density
Void ratio = (0.824 - 0.484) / 0.484 = 0.7
6. Calculate the degree of saturation:
Degree of saturation = (Mass of water / (Volume of specimen x Unit weight of water)) x 100%
Unit weight of water = g x 9.81 = 2.68 x 9.81 = 26.273 gm/cc
Volume of solids = Volume of specimen - Volume of voids
Volume of solids = Volume of specimen / (1 + Void ratio)
Volume of solids = 24.66 / (1 + 0.7) = 14.50 cc
Volume of voids = Volume of specimen - Volume of solids
Volume of voids = 24.66 - 14.50 = 10.16 cc
Degree of saturation = (14.28 / (14.50 x 26.273)) x 100% = 20.33%
Conclusion:
- Void ratio of the soil specimen = 0.7
- Degree of saturation of the soil specimen = 20.33%